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marta [7]
3 years ago
6

How is technology similar to printing words on a page?

Chemistry
2 answers:
drek231 [11]3 years ago
6 0
Because your still writing whether its on an online document or writing on a piece of paper.Its the same thing

Hope this helped :))
lesantik [10]3 years ago
5 0
Because on both of them you are typing/writing something.
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QUIZ SCIENCE:
vlabodo [156]
1. A soluble salt can be prepared by reacting an acid with a suitable insoluble reactant including:

a metal
a metal oxide
a carbonate
3. I don’t know this one
4. A term base or glossary is a database containing single words or expressions related to a specific subject.
5. Strong acid is an acid that ionizes completely in aqueous solution. It always loses a proton (H+) when dissolved in water. Weak acid is an acid that ionizes partially in a solution. ... Because the rate of reaction depends upon the degree of dissociation αand strong acids have higher degrees of dissociation.

im not sure of the rest
7 0
2 years ago
How many molecules of CO2 are present
allochka39001 [22]
Where’s the question or equation
6 0
3 years ago
Isotopes ____________ the atomic mass of an element because they have a ____________ number of neutrons.
blondinia [14]
B. Increase or decrease, different
8 0
3 years ago
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If a Ferrari with an initial velocity of 10m/s accelerates at a rate of 5m/s2 for 3 seconds. What will it’s final velocity be?
Reika [66]

Answer:

<em><u>V = 25 m/s</u></em>

Explanation:

From first equation of motion, V = U + at

V = 10 + ( 5×3 )

V = 25 m/s

4 0
3 years ago
A first-order reaction has a half-life of 16.7 s . How long does it take for the concentration of the reactant in the reaction t
andrew11 [14]

It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.

A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.

Assume the initial concentration is 1.00 mol/L. Then,

\text{1.00 mol/L }\stackrel{\text{1st half-life }}{\longrightarrow}\text{ 0.50 mol/L } \stackrel{\text{ 2nd half-life }}{\longrightarrow}\text{0.25 mol/L}\\

The concentration drops to one-fourth of its initial value in two half-lives.

∴ Time = 2 × 16.7 s = 33.4 s

5 0
3 years ago
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