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ira [324]
3 years ago
15

Titanium and chlorine react to form titanium(IV) chloride, like this:

Chemistry
1 answer:
leva [86]3 years ago
4 0

Answer:

the value of equilibrium constant for the reaction is 8.5 * 10⁷

Explanation:

Ti(s) + 2 Cl₂(g) ⇄ TiCl₄(l)

equilibrium constant Kc = \frac{1}{[Cl_2]^2}

Given that,

We are given:

Equilibrium amount of titanium = 2.93 g

Equilibrium amount of titanium tetrachloride = 2.02 g

Equilibrium amount of chlorine gas = 1.67 g

We calculate the No of mole = mass / molar mass

mass of chlorine gas = 1.67 g

Molar mass of chlorine gas = 71 g/mol

mole of chlorine = 1.67 / 71

= 7.0L

Concentration of chlorine is = no of mole / volume

= 0.024 / 7

= 3.43 * 10⁻³M

equilibrium constant Kc  = \frac{1}{[Cl_2]^2}

= \frac{1}{[3.43 * 10^-^3]^2}

= 8.5 * 10⁷

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Explanation:

1.

Given parameters:

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Unknown:

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Given parameters:

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