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Ad libitum [116K]
3 years ago
14

What is the ph of a solution with [oh-] = 2.6 × 10^-3 m?

Chemistry
1 answer:
Leto [7]3 years ago
6 0
POH = - log [ OH⁻]

pOH = - log [ 2.6x10⁻³]

pOH = 2.58

pH + pOH = 14

pH + 2.58 = 14

pH = 14 - 2.58

pH = 11.42

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A sample of potassium has an average atomic mass of 39.0983amu. There are three isotopic forms of potassium element in the sampl
igomit [66]

Answer:

Percent Composition of 41K = 6.7302%

Explanation:

The explination is in the image.

7 0
3 years ago
1. Mixing is a physical change.<br> True or false
Hitman42 [59]

Answer:

true

Explanation:

if u mix it can explode which is a chemical reaction

5 0
3 years ago
Read 2 more answers
For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac
barxatty [35]
First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

O2 = 16*2 = 32 g/mol

From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3: 

when 245.2 KClO3 gives → 96 g  O2

   2.72 g KClO3 gives →  X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

    = 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

     0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

       = 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

       83.6 Kg KClO3 gives  →  X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

     = 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

        22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

      = 8.8 mg of O2

     

 


7 0
4 years ago
Would the N=O bond in HNO2 be longer, shorter, or the same length as the N-O bonds in NO2-?
aivan3 [116]

Explanation:

Bond order is inversely proportional to the bond length.

B.O\propto \frac{1}{B.L}

In HNO_2 molecule. one nitrogen is double bonded to nitrogen and one oxygen is single bonded to nitrogen and hydrogen bond.

  • Bond order between the (N=O) bond is 2 which means that bond length between the (N=O) bond is shorter than that of the N-O bond.
  • Bond order between the (N-O) bond is 1 which means that bond length of the N-O bond is longer than that of the bond length of (N=O) bond.
3 0
3 years ago
Read 2 more answers
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
4 years ago
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