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tamaranim1 [39]
3 years ago
6

Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {

\rm{c}}_{10} {\rm{h}}_{15} {\rm{on(}}aq{\rm{)}} + {\rm{h}}_2 {\rm{o}}(l{\rm{)}} \overrightarrow{\leftarrow} {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ + (aq) + {\rm{oh}}^ - (aq) a 0.035 {\rm m} solution of ephedrine has a{\rm ph} of 11.33. what is the equilibrium concentration of{\rm{c}}_{10} {\rm{h}}_{15} {\rm{on}}, {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ +, and oh-.
Chemistry
1 answer:
sashaice [31]3 years ago
3 0

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH</span>⁻] = 10∧(-2,67) = 0,00213 M.<span>
[OH</span>⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.<span>
[</span>C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.<span>
Kb = [OH</span>⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].<span>
Kb = (</span>0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

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Hope this helps :)


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