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tamaranim1 [39]
3 years ago
6

Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {

\rm{c}}_{10} {\rm{h}}_{15} {\rm{on(}}aq{\rm{)}} + {\rm{h}}_2 {\rm{o}}(l{\rm{)}} \overrightarrow{\leftarrow} {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ + (aq) + {\rm{oh}}^ - (aq) a 0.035 {\rm m} solution of ephedrine has a{\rm ph} of 11.33. what is the equilibrium concentration of{\rm{c}}_{10} {\rm{h}}_{15} {\rm{on}}, {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ +, and oh-.
Chemistry
1 answer:
sashaice [31]3 years ago
3 0

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH</span>⁻] = 10∧(-2,67) = 0,00213 M.<span>
[OH</span>⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.<span>
[</span>C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.<span>
Kb = [OH</span>⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].<span>
Kb = (</span>0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

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3 years ago
3/4(x-2)=x-1 please answer me ​
Elan Coil [88]

Answer:

-2

Explanation:

3/2 (x-2) = x-1

<=> 3/4 x - 3/2 = x-1

<=> 3/4 x - x = 3/2 -1

<=> -1/4 x =1/2

<=> x= -2

3 0
3 years ago
Read 2 more answers
How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
meriva

Answer:

\large \boxed{\text{77.4 mL}}

Explanation:

                Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

    V/mL:     249

c/mol·L⁻¹:  0.0443     0.285

1. Calculate the moles of Ba(OH)₂

\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1  mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}

3. Calculate the volume of HCl

V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}

8 0
3 years ago
The following balanced equation shows the formation of water. 2H2 + O2 2H2O How many moles of oxygen (O2) are required to comple
motikmotik

Answer:

13.7 moles of O₂ are needed

Explanation:

In order to find the moles of reactants that may react to make the products we need to determine the reaction:

Reactants are hydrogen and oxygen

Product: Water

2 moles of hydrogen can react to 1 mol of oxygen and produce 2 moles of water.

Balanced reaction: 2H₂(g) + O₂(g) →  2H₂O(l)

If 2 moles of hydrogen need 1 mol of oxygen to react

Therefore, 27.4 moles of H₂ must need (27.4 .1) / 2 = 13.7 moles of O₂

8 0
2 years ago
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