Answer:
No
Explanation:
Depending on the mass of the horse and the speed, velocity will change.
It will result in an increase in the rate of rxn
Answer : The mole fraction and partial pressure of
and
gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.
Explanation : Given,
Moles of
= 1.79 mole
Moles of
= 1.20 mole
Moles of
= 3.71 mole
Now we have to calculate the mole fraction of
and
gases.


and,


and,


Thus, the mole fraction of
and
gases are, 0.267, 0.179 and 0.554 respectively.
Now we have to calculate the partial pressure of
and
gases.
According to the Raoult's law,

where,
= partial pressure of gas
= total pressure of gas = 5.78 atm
= mole fraction of gas


and,


and,


Thus, the partial pressure of
and
gases are, 1.54, 1.03 and 3.20 atm respectively.
<span>My hypothesis is the the cell, having a higher osmolarity than the solution of of nacl in the beaker, will have an osmosis reaction releasing into the solution of nacl. This will continue until both cell and solution reach a balance.</span>
We have that the molecular weight (3sf) of the compound (g/mol)

From the question we are told
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).
Generally the equation for the Rouault's law is mathematically given as
P=P_0 N

Therefore
The molecular weight (3sf) of the compound (g/mol)
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