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3 years ago

1. Mixing is a physical change. True or false

Chemistry

2 answers:

Arada [10]3 years ago

6 0

Answer:

false it is a chemical change

Hitman42 [59]3 years ago

5 0

Answer:

true

Explanation:

if u mix it can explode which is a chemical reaction

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

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3 years ago

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2Na2SO4 :How many atoms for each element are in the formula?<br><br> S=<br> O=<br> Na=

yuradex [85]

Answer:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

Explanation:

The given compound is:

2Na₂SO₄

An element is a distinct substance that cannot be split up into simpler substances.

So;

Number of atoms of elements here are:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

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2 years ago

How can the pH of a solution be calculated if the pOH is known?

daser333 [38]

the answer is d guys

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3 years ago

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If 3.5 g H2 react with 18.7 g O2 what is the limiting reactant?

Pachacha [2.7K]

O2 is the limiting reactant

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3 years ago

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HELP PLEASE (Solve this problem using the appropriate law). what is the volume of 0.382 moles of hydrogen gas at 1.50 atmosphere

kaheart [24]

Answer:

V = 6.17 L

Explanation:

Given data:

Volume = ?

Number of moles = 0.382 mol

Pressure = 1.50 atm

Temperature = 295 k

R = 0.0821 L. atm. /mol. k

Solution:

According to ideal gas equation:

PV= nRT

V = nRT/P

V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm

V = 9.252 L. atm. / 1.50 atm

V = 6.17 L

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