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andre [41]
2 years ago
5

Two objects have the same center point of the circle, but are located at different positions away from the center point. Each ob

ject is moving with uniform circular motion.
Which would describe the tangential speed of the objects?

both objects would have the same tangential speed
the object with the smaller radius has a faster tangential speed
the object with the larger radius has a faster tangential speed
both objects would have oscillating tangential speeds
Physics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

The object with the larger radius has a faster tangential speed. Tangential speed is related to both rotational speed and radial distance from the rotating axis.

<h3>What is uniform circular motion?</h3>

Uniform circular motion is a type of motion of a particle around a circle at a constant speed. The magnitude of the speed of the particle is constant.While the direction is changing continuously.

Tangential speed is related to both rotational speed and radial distance from the rotating axis.

The object with the larger radius has a faster tangential speed.

Hence, option C is correct.

To learn more about the uniform circular motion, refer to the link;

brainly.com/question/2285236

#SPJ1

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standing side by side, you and a friend step off a bridge and fall for 1.6s to the water below. your friend goes first, and you
Andrew [12]

(a) The distance will be more than 2.0 meters.

In fact, you starts your fall after your friend has already fallen 2.0 meters. This means that your friend has already accelerated for a while, therefore his velocity will be greater than yours. But this statement will be actually true for the entire fall, since you has some delay, therefore when your friend will hit the water, the separation between you and him will be greater than the initial separation of 2.0 meters.


b) First of all we need to calculate the height of the bridge with respect to the water. We know that you take 1.6 s to fall down, therefore we can use the following equation:

S=\frac{1}{2}gt^2=\frac{1}{2}(9.81 m/s^2)(1.6s)^2=12.56 m

We know that your friend will take 1.6 s to falls down. Instead, you start your jump after he has already fallen 2.0 m, therefore after a time given by the equation:

S=\frac{1}{2}gt^2

Using S=2.0 m,

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(2.0 m)}{9.81 m/s^2}}=0.64 s

So we know that you start your fall 0.64 s after your friend. Therefore, now we can find how much did you fall between the moment you started your fall (0.64 s) and the moment your friend hits the water (1.6 s). Using

t=1.6 s-0.64 s=0.96 s

we find

S=\frac{1}{2}gt^2=\frac{1}{2}(9.81 m/s^2)(0.96 s)^2 =4.52 m

So, when your friend hits the water, you just covered 4.52 m, while he already covered 12.56 m. Therefore, the separation between you and your friend is more than 2 meters.

8 0
3 years ago
A boat floats south on the Amazon River at a speed of 6 m/s. The boat and
EleoNora [17]

Explanation:

Take south to be negative.

a. Momentum is mass times velocity.

p = mv

p = (540 kg) (-6 m/s)

p = -3240 kg m/s

p = 3240 kg m/s south

b. Impulse = change in momentum

J = Δp

Since the mass is constant:

J = mΔv

J = (540 kg) (-4 m/s − (-6 m/s))

J = 1080 kg m/s

J = 1080 kg m/s north

7 0
3 years ago
A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

       N = W_{y}

X axis

       F1 - fr - Wₓ = 0

       fr = F1 - Wₓ

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     cos θ = W_{y} / W

      Wₓ = W sin θ

      W_{y} = W cos θ

We substitute

      fr = F1 - W sin θ

Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

4 0
3 years ago
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expeople1 [14]

Answer: Distance= 100,000 km

   Mass= 15 million kg        Mass= 5 million kg

3 0
3 years ago
Read 2 more answers
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Rashid [163]

Answer:

1.03 m/s

Explanation:

I'm too lazy to write the explanation down but my teacher graded this and it was right

6 0
3 years ago
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