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andre [41]
2 years ago
5

Two objects have the same center point of the circle, but are located at different positions away from the center point. Each ob

ject is moving with uniform circular motion.
Which would describe the tangential speed of the objects?

both objects would have the same tangential speed
the object with the smaller radius has a faster tangential speed
the object with the larger radius has a faster tangential speed
both objects would have oscillating tangential speeds
Physics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

The object with the larger radius has a faster tangential speed. Tangential speed is related to both rotational speed and radial distance from the rotating axis.

<h3>What is uniform circular motion?</h3>

Uniform circular motion is a type of motion of a particle around a circle at a constant speed. The magnitude of the speed of the particle is constant.While the direction is changing continuously.

Tangential speed is related to both rotational speed and radial distance from the rotating axis.

The object with the larger radius has a faster tangential speed.

Hence, option C is correct.

To learn more about the uniform circular motion, refer to the link;

brainly.com/question/2285236

#SPJ1

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7) Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in
viva [34]

Answer:

A, 0.59A

Explanation:

The total resistance in the circuit is the resistances in parallel plus that in series.

Total resistance for those in parallel is;

1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)

1/(31/60)= 60/31 ohms

Hence total resistance of the circuit is;

60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms

To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.

Voltage drop on the 2 ohm resistance is;

Current on the 2 ohm resistor × 2 ohms

V = I ×R ; I - current

R - resistance

Current drop on the 2ohm resistance is;

Total voltage in the circuit/ total resistance in the circuit

12/3.94= 3.05A

Voltage drop on the 2 ohm resistance;

3.05 × 2 = 6.10volts

Hence voltage drop on the parallel resistance would be ;

12-6.10= 5.90V

Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.

That said, the current drop on the 10 ohm resistor would be;

5.90/10 = 0.59A

Remember V= I× R so that I = V/R

6 0
4 years ago
Question 2
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B. True give me branliest
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3 years ago
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A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck tra
gavmur [86]
I believe it would be 144 m!
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3 years ago
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An amplifier produces a sound wave with a power of 1.00 μW (micro-Watt). If it is a point source and radiates uniformly in all d
gtnhenbr [62]

Answer:

(a) I=8.84*10^{-9}W/m^{2}

(b) \beta =39.46dB

Explanation:

Given data

The source is 1.00 μW

The point is 3m away from the point source

For Part (a)

The intensity at a certain distance from a point source that emits sound wave is given as:

I=\frac{P_{s} }{4\pi r^{2} }\\I=\frac{1*10^{-6}W  }{4\pi (3m)^{2} } \\I=8.84*10^{-9}W/m^{2}

For Part (b)

The Sound level is given by

β=(10dB)×log(I/I₀)

Where

I₀=1×10⁻¹²W/m²

Substitute the given values to find Sound level

So

\beta =(10dB)log(\frac{8.84*10^{-9}W/m^{2}  }{1*10^{-12}W/m^{2}} )\\\beta =39.46dB

4 0
3 years ago
When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , dete
Maslowich

Answer:

t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

Explanation:

From the question we are told that

   The  hydraulic conductivity is  Ks =  10\ mm/hr

    The  effective matrix potential Ns  =  20 \ mm

    The  intensity of  rainfall is  I  =  30 \ mm/hr

    The runoff rate R =  15 \  mm/hr

Generally the run off rate is mathematically represented as  

      R = (I - Ks) t

Here t is the amount of runoff generated

=>   15 = (30 - 10) t

=>  t  =  0.75 \ hr

converting to minutes

    t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

3 0
3 years ago
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