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gulaghasi [49]
3 years ago
7

Smallest unit that consists of at least one atom

Physics
2 answers:
notsponge [240]3 years ago
6 0
<span>Smallest unit that consists of at least one atom is d

</span>
valkas [14]3 years ago
5 0
Yes its D. Molecules is the answer because A molecule is an electrically neutral group of two or more atoms held together by chemical bonds.
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How much force is needed to accelerate a 2500 kg car at a rate of 4m/s²?
Vika [28.1K]

Answer:

Momentum (p) is equal to the product of an object's mass (m) and its change in velocity (v).

Change in velocity (v) results in change in momentum (p), which is equal to impulse. Impulse (J) is also equal to an applied force (F) over a period of time (t).

Combining p=mv and J=F t together:

m (v final - v initial) = F t

(2,500 kg) (70 m/s - 30 m/s) = F (10 s)

Explanation:

Solving for F we get:

10,000 N of force

4 0
2 years ago
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The balls in the image above have different masses and speeds. Fill in the blanks in the following sentence: Ball ___ has the gr
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Yes I’m going home I was finna was your birthday and I got to get my kids ready
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3 years ago
Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th
Akimi4 [234]

Answer:

a) The distance of spectator A to the player is 79.2 m

b) The distance of spectator B to the player is 43.9 m

c) The distance between the two spectators is 90.6 m

Explanation:

a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:

x = v * t

where:

x = position of the spectators

v = speed of sound

t = time

Then, the position for spectator A relative to the player is:

x = 343 m/s * 0.231 s = 79.2 m

b)For spectator B:

x = 343 m/s * 0.128 s

x = 43.9 m

The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.

c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:

(Distance AB)² = A² + B²

(Distance AB)² = (79.2 m)² + (43.9 m)²

Distance AB = 90. 6 m

6 0
4 years ago
Need help on this please
Likurg_2 [28]
Build up of pressure between tectonic plates .
8 0
3 years ago
A myopic (nearsighted) person has a far point distance of 150 cm. What is the refractive power of his ideally prescribed eyeglas
sukhopar [10]

Answer:0.68 D

Explanation:

Given

Person has a far point distance of 150 cm

i.e. d_i=-150 cm

therefore

v=-150+3=-147 cm

From Lens Formula

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}

Here the object distance is infinity

\frac{1}{f}=\frac{-1}{147}+\frac{1}{\infty}

Therefore f=-147 cm

and f=\frac{1}{P}

P=-\frac{100}{147}

P=-0.68 D

8 0
3 years ago
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