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3 years ago

ok so for 99 points(not multiple choice)what is one way to separate salt from grains NO MULTIPLE CHOICE

Physics

2 answers:

Nikitich [7]3 years ago

7 0

You can put it in water, strain the water with a colander so the grain will stay in, then warm up the water.

iragen [17]3 years ago

6 0

Place mixtuer into water. stir mixture into water, wait untill salt is disoldved. Strain out grain. boil water intill only salt is left. Hope this helps! ^-^

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A constant force is applied to an object, causing the object to accelerate at 10 m/s^2. What will the acceleration be if: a) The

Liula [17]

What you need to know is that the force is

F=ma

The force is the product of mass and acceleration

this means that the acceleration is

a=F/m

a) The force is halved?
this means that f will be $\frac{F}{2}$ now:

a= $\frac{F}{2m}$

So the accelaration will also he halved (it's the original acceleratation divided by 2)

b) The object's mass is halved?
a= $\frac{F}{m/2}$ =a= $\frac{F2}{m}$

which is the original acceleration times two!! so it will double

c) The force and the object's mass are both halved?
now we have

a= $\frac{F/2}{m/2}$ =a= $\frac{2F}{2m}$ =a= $\frac{F}{m}$

so they will cancel each other out and the acceleration will stay the same!

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Nana76 [90]

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3 years ago

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bonufazy [111]

Answer:

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A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N

mart [117]

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force( $F_{A}$ ) and the kinetic frictional force( $F_{R}$ ). i.e

F = $F_{A}$ - $F_{R}$ -----------------(i)

Note that;

$F_{R}$ = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = $F_{A}$ - μmg -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

$F_{A}$ = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

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2 years ago