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amm1812
3 years ago
7

In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con

tainer, what would be the equilibrium concentration of BrCl?
Chemistry
1 answer:
klemol [59]3 years ago
7 0

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by =K_p=0.150

Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)

initial

0       0         0.500 atm

At equilbrium

p      p       (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

 K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}

0.150=\frac{(0.500-2p)^2}{p\times p}

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

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