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3 years ago

Antifreeze is added to a car's radiator to protect it. Which of the following

Chemistry

1 answer:

zhenek [66]3 years ago

5 0

Answer:

the correct answer is b antifreeze protects the radiator during summer in winter.

Explanation:

Antifreeze is (typically mixed with water) to help manage the engine during extreme temperatures. As the temperature fluctuates between hot and cold coolant is distributed throughout the engine block to sustain even operating temperature.

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A train travels 803.98 meters in 1 minute what is the trains average rate of speed

TEA [102]

Answer:

Approximately 13.4 meters per second (m/s)

Explanation:

We can divide the distance by 60 seconds to find the trains average rate of speed.

803.98 / 60 ≈ 13.4

Best of Luck!

7 0

3 years ago

When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t

OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

$Mn(s)+2HCl(aq)\rightarrow MnCl_2(aq)+H_2(g)$

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

$m=1.00 g/mL\times 100.0 mL = 100 g$

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

$q=m\times c\times (T_{final}-T_{initial})$

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = $4.18 J/^oC$

$T_{final}$ = final temperature = $23.1^oC$

$T_{initial}$ = initial temperature = $28.9^oC$

Now put all the given values in the above formula, we get:

$q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC$

$q=2,242.4 J=2.242 kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = $\frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol$

$\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol$

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

8 0

3 years ago

What happens to a gas that is enclosed in a rigid container when the temperature of the gas is increased?

yanalaym [24]

A) - heat makes particles move faster, which usually makes the substance as a whole expand, but if the gas cannot expand the pressure will increase instead

7 0

3 years ago

How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas?

Elina [12.6K]

Answer: 631.8 g

Explanation:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

It can be seen from the balanced chemical equation, 2 moles of ethane reacts with 7 moles of Oxygen gas to produce 4 moles of carbon dioxide and 6 moles of water.

Ethane is the limiting reagent as it limits the formation of product.

Thus, if 2 moles of ethane produce 6 moles of water.

11.7 moles moles of ethane produce= $\frac{6}{2}\times 11.7=35.1 moles$ of water.

Mass of water= no of moles $\times$ Molar mass

Mass of water= 35.1 $\times$ 18g/mol= 631.8 g

4 0

3 years ago

Read 2 more answers

A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole

swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

$\tt 0.1\times 32+0.9\times M=3.2+0.9M$

Graham's Law :

$\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol$

7 0

3 years ago