All categories

3 years ago

What are the advantages of using a blue flame instead of a yellow one for heating objects?

1 answer:

8 0

A blue flame is a manifestation that the combustion process is complete where there are no formation of carbon monoxide. On the other hand, a yellow flame represents an in complete combustion. Generally, a blue flame is much hotter as compared to a yellow flame so it heat things up faster. Also, it is a much cleaner flame as it does not produce soot which leaves a black residue on the material being heated.

You might be interested in

The motor of a ski boat generates an average power of 2.74 × 10^4 W when the boat is moving at a constant speed of 14.3 m/s. Whe

Roman55 [17]

Answer:

T = 4517.48 N

Explanation:

It is given that,

Average power of the motor, $P_1=2.74\times 10^4\ W$

Speed of the boat, $v_1=14.3\ m/s$

Force or tension acting on the motor at this point is given by :

$P=T\times v$

$T=\dfrac{P_1}{v_1}$

$T=\dfrac{2.74\times 10^4}{14.3}$

T = 1916.08 N

Average power generated by the engine, $P_2=9.2\times 10^4\ W$

Force or tension acting on the motor at this point is given by :

$P=T\times v$

$T=\dfrac{P_2}{v_2}$

$T=\dfrac{9.2\times 10^4}{14.3}$

T = 6433.56 N

So, the tension in the tow rope that is pulling the skier is, T = 6433.56 N - 1916.08 N = 4517.48 N

4 0

3 years ago

To keep the blood flowing and bring energy

Rufina [12.5K]

Answer:

Glucose

☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺

8 0

3 years ago

Read 2 more answers

Matt is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe

Olin [163]

(150 meters) / (18 seconds) = 8.33 meters per second

4 0

3 years ago

A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the proce

Grace [21]

The angular acceleration of the wheel approximately <u>-0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s</u>.
It need approximately <u>14.474 s</u> to come to rest.

<h2>Introduction</h2>

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

1 rotation = 2π rad
1 rps = 2π rad/s
1 rpm = $\sf{\frac{1}{60} \: rps}$ = $\sf{\frac{1}{30}\pi \: rad/s}$

<h2>Formula Used</h2>

The following equations apply to proportionally changes circular motion:

<h3>Relationship between Angular Acceleration and Change of Angular Velocity </h3>

$\boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}$

With the following conditions:

$\sf{\omega_t}$ = final angular velocity (rad/s)
$\sf{\omega_0}$ = initial angular velocity (rad/s)
$\sf{\alpha}$ = angular acceleration (rad/s²)
t = interval of the time (s)

<h3>Relationship between Angular Acceleration and Change of $\sf{\theta}$ (Angle of Rotation) </h3>

$\boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}$

$\boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}$

With the following condition :

$\sf{\theta}$ = change of the sudut (rad)
$\sf{\alpha}$ = angular acceleration (rad/s²)
t = interval of the time (s)
$\sf{\omega_t}$ = final angular velocity (rad/s)
$\sf{\omega_0}$ = initial angular velocity (rad/s)

<h2>Problem Solving</h2>

We know that :

$\sf{\omega_t}$ = final angular velocity = 0 rad/s >> see in the sentence "in the process of coming to rest."
$\sf{\omega_0}$ = initial angular velocity = 11 rad/s
$\sf{\theta}$ = change of the sudut = 80.0 rad

What was asked :

$\sf{\alpha}$ = angular acceleration = ... rad/s²
t = interval of the time = ... s

Step by step :

$\sf{\alpha}$ = ... rad/s²

$\sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}$

$\sf{0^2= (11)^2 + 2 \times \alpha \times 80}$

$\sf{0 = 121 + 160 \alpha}$

$\sf{-160 \alpha = 121}$

$\sf{\alpha = \frac{121}{-160}}$

$\sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}$

t = ... s

$\sf{\alpha = \frac{\omega_0 - \omega_t}{t}}$

$\sf{-0.76 = \frac{0 - 11}{t}}$

$\sf{-0.76t = -11}$

$\sf{t = \frac{- 11}{-0.76}}$

$\boxed{\sf{t \approx 14.474 \: s}}$

<h3>Conclusion</h3>

So :

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.
It need approximately 14.474 s to come to rest.

5 0

2 years ago

When driving at night, only use your high-beam headlights___

zzz [600]

Answer:

Explanation:

While answer C may sound correct, Answer B is makes more sense. We know you cant use High-beam lights when u cant see ongoing traffic because it could affect the other driver coming across from you. Its good to use it when legal and safe, but in that term I still don't believe there's no reason for HIGH-beamed. That's this leaves B, when you are on u lighted streets.

6 0

3 years ago