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3 years ago

12

Most moving objects change speed or direction at some point because _____ forces exist nearly everywhere. A. net B. normal C. ba

lanced D. unbalanced

2 answers:

dangina [55]3 years ago

8 0

The answer is D. Unbalanced

This is because in order to change the speed or direction of an object, unbalanced forces need to be working on it.

Hope that helps! :)

Harman [31]3 years ago

5 0

D. Unbalanced

Good Luck

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A soccer player icks a rock horizontally off a 40m high cliff into a pool f water if the player hears the sound of the splash s

Semenov [28]

Answer:

v = 9.936 m/s

Explanation:

given,

height of cliff = 40 m

speed of sound = 343 m/s

assuming that time to reach the sound to the player = 3 s

now,

time taken to fall of ball

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 40}{9.8}}$

t = 2.857 s

distance

d = v x t

d = v x 2.875

time traveled by the sound before reaching the player

$t_0 = t - t_{fall}$

$t_0 = 3 - 2.875$

$t_0 = 0.143 s$

distance traveled by the wave in this time'

r = 0.143 x 343

r= 49.05 m

now,

we know.

d² + h² = r²

d² + 40² = 49.05²

d =28.387 m

v x 2.875=28.387 m

v = 9.936 m/s

7 0

3 years ago

Given your choice for part 1, would it be possible, in principle under ideal circumstances, for a balloon to stick to a wall ind

podryga [215]

Answer:

Explanation:1)Rub a balloon on your head and stick it to the wall. And it sticks—very nice. We’ve

talked in lecture about why it sticks. This question is about why, after a while, it fall off.

Consider each of the following explanations.

i) It falls because it uses up the energy you put on it when you rubbed it.

ii) It falls because it uses up the charge you put on it when you rubbed it.

iii) It falls because the energy you put on it slowly leaks off into the wall or the air.

iv) It falls because the charge you put on it slowly leaks off into the wall or the air.

Answer: It falls because the charge you put on it slowly leaks off into the wall or the air.

2) Given your choice for part a, would it be possible, in principle under ideal

circumstances, for a balloon to stick to a wall indefinitely?

Answer: If you can keep the charge from leaving the balloon, And if the

wall is a very good insulator also this will prevent the ball from falling.

8 0

3 years ago

Suppose that a constant force is applied to an object with a mass of 12kg, it’s creates an acceleration of 5m/s^2. The accelerat

Klio2033 [76]

Answer:

Mass of second object will be 15 kg

Explanation:

We have given mass of first object = 12 kg

Acceleration $a=5m/sec^2$

According to second law of motion we know that force F = MA

So force $F=12\times 5=60N$

As the same force is applied to the second object of acceleration $a=4m/Sec^2$

So force = ma

$60=m\times 4$

m = 15 kg

So mass of second object will be 15 kg

5 0

3 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

Mumz [18]

Answer:

Part a)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Explanation:

Red car

mass = 1000 kg

speed = 10 m/s

Yellow car

mass = 2000 kg

speed = 5 m/s

Blue car

mass = 500 kg

speed = 20 m/s

Light Blue car

mass = 1000 kg

speed = 20 m/s

Green car

mass = 500 kg

speed = 10 m/s

Purple car

mass = 4000 kg

speed = 5 m/s

Part a)

Now we know that momentum of each car is product of mass and velocity

so we will have

Red Car

$P_1 = m v$

$P_1 = (1000)(10)$

$P_1 = 10^4 kg m/s$

Yellow Car

$P_2 = m v$

$P_2 = (2000)(5)$

$P_2 = 10^4 kg m/s$

Blue Car

$P_3 = m v$

$P_3 = (500)(20)$

$P_3 = 10^4 kg m/s$

Light Blue Car

$P_4 = m v$

$P_4 = (1000)(20)$

$P_4 = 2\times 10^4 kg m/s$

Green Car

$P_5 = m v$

$P_5 = (500)(10)$

$P_5 = 5 \times 10^3 kg m/s$

Purple Car

$P_6 = m v$

$P_6 = (4000)(5)$

$P_6 = 2\times 10^4 kg m/s$

So the momentum is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Force is defined as rate of change in momentum

Now let say all cars will stop in same time interval

so we will have

$Force = \frac{impulse}{time}$

so we will have

force is in same order as that of impulse

so it is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

5 0

4 years ago

Read 2 more answers

Two diamonds begin a free fall from rest and from the same height 1 second apart.

Bumek [7]

Answer:

Explanation:

let t be time since the second diamond is released

a) y = ½g(t + 1)²

b) y' = ½g(t)²

c)

25 = ½g(t + 1)² - ½gt²

25 = ½g(t² + 2t + 1) - ½gt²

25 = ½gt² + gt + ½g - ½gt²

25 = g(t + ½)

t + ½ = 25 / g

t = (25 / g) - ½

t = (25 / 9.8) - ½

t = 2.05102... ≈ 2.1 s

6 0

3 years ago