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Levart [38]
3 years ago
15

All are examples of electromagnetic energy except ______.

Physics
2 answers:
kkurt [141]3 years ago
4 0
All are examples of electromagnetic energy except <span>circles forming when a rock drops into a pool. The correct option among all the options that are given in the question is the third option or option "C". The other choices can be negated. I hope that this is the answer that has actually come to your help.</span>
yulyashka [42]3 years ago
3 0

Answer:

Circles forming when a rock drops into a pool.

Explanation:

Dispersion of light forming rainbow and X-ray usage are the examples of electromagnetic energy.

But when a  rock drops into a pool it has some energy due to gravity. When it hits the surface of water it tries to penetrate through water thus removing certain amount of water from that place. As the energy moves away, it forms ripples ( waves).

Thus formation of circles by dropping a rock into pool is an example of mechanical energy, not electromagnetic energy.

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Most of the energy we use on earth comes from the sun—how does that energy(light and thermal)end up?

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3 years ago
What is the function of nucleus in plant and animal cells
tatiyna
In animal cells, vacuoles are generally small. Vacuoles tend to be large in plant cells and play several roles: storing nutrients and waste products, helping increase cell size during growth, and even acting much like lysosomes of animal cells. The plant cell vacuole also regulates turgor pressure in the cell.
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4 years ago
Find an expression for the electric field e⃗ at the center of the semicircle. hint: a small piece of arc length δs spans a small
ahrayia [7]
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by 

<span>C = 2L = 2*pi*R ---> R = L/pi </span>

<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>

<span>we can define a small charge dq as </span>

<span>dq = l*ds = l*R*da </span>

<span>So the electric field can be written as: </span>

<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>

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8 0
4 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
OverLord2011 [107]

Answer:

a) h = 13,205.4 m

b)  r_f = 2.12 106 m

c)        e% = 0.68%

Explanation:

a) This is an exercise we are asked to use energy conservation,

Starting point. On the surface of Mimas

        Em₀ = K = ½ m v²

Final point. Where the ball stops

       Em_{f} = U = m g h

        Em₀ = Em_{f}

        ½ m v² = m g h

         h = ½ v² / g

let's calculate

         h = ½ 41² / 0.0636

         h = 13,205.4 m

b) For this part we are asked to use the law of universal gravitation, write the energy

starting point. Satellite surface

           Em₀ = K + U = ½ m v² - GmM / r_o

final point. Where the ball stops

            Em_{f}= U = - G mM / r_f

          Em₀ = Em_{f}

          ½ m v² - G m M / r_o = - G mM / r_f

In this case all distances are measured from the center of the satellite

         1 / rf = 1 / GM (-½ v² + G M / r_o)

     

let's calculate

         1 / rf = 1 / (6.67 10⁻¹¹ 3.75 10¹⁹) (- ½ 41 2 + 6.67 10⁻¹¹ 3.75 10¹⁹ / 1.98 105)

         1 / r_f = 3,998 10⁻¹¹(-840.5 + 12.63 10³)

          1 / r_f = 4,714 10⁻⁷

          r_f = 1 / 4,715 10⁻⁷

          r_f = 2.12 106 m

to measure this distance from the satellite surface

          r_f ’= r_f - r_o

          r_f ’= 2.12 106 - 1.98 105

         r_f ’= 1,922 106 m

c) the percentage difference is

          e% = 13 205.4 / 1,922 106 100

          e% = 0.68%

The estimate of part a is a little low

6 0
4 years ago
2 forces are acting on a body. I forgot the body doesn't it's position or shape, the forces.......a)must be of equal magnitude b
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Answer:

C

Explanation:

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5 0
4 years ago
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