B = magnetic field in the cyclotron = 0.400 T
q = magnitude of charge on a proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷ kg
f = frequency of revolution of proton in the cyclotron = ?
v = speed of electromagnetic waves = 3 x 10⁸ m/s
λ = wavelength of electromagnetic wave = ?
Frequency of revolution of proton in the cyclotron is given as
f = qB/(2πm)
inserting the values
f = (1.6 x 10⁻¹⁹)(0.400)/(2 (3.14) (1.67 x 10⁻²⁷))
f = 6.1 x 10⁶ Hz
wavelength of electromagnetic wave is given as
λ = v/f
λ = (3 x 10⁸)/(6.1 x 10⁶)
λ = 49.2 m
connexus unit 8 lesson 1 PRACTICE!
1) B
2) C
3) A
4) C
5) B
6) A
7) D
8) A
9) D
10) A
11) A
12) C
13) D
14) C
15) B
16) B
Hope this helps you guys out!
<h2>
C. 20 T</h2>
The strength of the magnetic field is equal to 20 Tesla.
<h3>
Explanation:</h3>
Given:
Induced potential difference = V = 12 V
Length of wire = L = 0.20 m
Speed of the moving wire = V = 3.0 m/s
Magnetic field strength = B = ?
A conductor, placed in a uniform magnetic field; when moved at a constant speed with respect to the field, leads to a changing magnetic flux, generating an electromotive force (EMF). Using, Faraday's law of magnetic induction, a moving conductor's induced EMF in terms of the magnetic field strength is given by :
......................(1)
where
E = Induced potential difference (EMF)
L = Length of the conductor
V = Speed of the conductor moved with respect to the magnetic field
B = Strength of uniform magnetic field
Rewriting equation (1) for B, we get

The strength of magnetic field is equal to 20 Tesla.
Answer:
For the distance range 50 to 500 km, the S-waves travel about 3.45 km/s and the P-waves around 8 km/s.
hope it helps.
The answer to this is electric force. Hope it helps