We will have the following:
First, the equation to use is the following:

Now, we transform the total distance the cat would need to travel:

So, the cat would need to travel 1.5 meters. ("d" in the equation).
Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.
Now, we know that the acceleration will be given by Earth's gravity, so:


So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.
Answer:
The Answer is gonna be B.
Air warms and rises.
Answer:
(2)


Explanation:
<u>a)Kinematics equation for the first ball:</u>


initial position is the building height
The ball reaches the ground, y=0, at t=t1:

(1)
Kinematics equation for the second ball:


initial position is the building height
the ball is dropped
The ball reaches the ground, y=0, at t=t2:

(2)
the second ball is dropped a time of 1.03s later than the first ball:
t2=t1-1.03 (3)
We solve the equations (1) (2) (3):






vo=8.9m/s

t2=t1-1.03 (3)
t2=3.29sg
(2)
b)
t1 must : t1>1.03 and t1>0
limit case: t1>1.03:





limit case: t1>0:



