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sweet [91]
4 years ago
12

A student must make a 3 m acid solution using a 5 m acid solution. which of these is the safest way to make the solution?

Chemistry
1 answer:
weqwewe [10]4 years ago
8 0
The motivation to abstain from adding water to concentrated acids is that, with a few acids, amid weakening, a considerable measure of warmth is discharged, by adding the corrosive to the water, the generally extensive measure of water will retain the warmth. On the off chance that you added water to concentrated corrosive when you initially beginning pouring the water, it could get sufficiently hot for the little measure of water that was filled all of a sudden bubble and splatter corrosive on you. Concentrated sulfuric corrosive is most famous for doing this, not all acids get that hot on weakening, but rather in the event that you make a propensity for continually adding the corrosive to water for every one of them, you can't turn out badly.
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What can you conclude from the hypothesis “If the temperature of the liquid is increased, then more sugar will dissolve because
sergeinik [125]
<h2>Answer with Explanation</h2>

This hypothesis concludes that the sugar dissolves faster in warm solution has to do with increased molecular motion because the combined power in the warm solution makes molecules in water to travel quicker and sucrose molecules to fluctuate faster which produced a continued evolution favors to make the connections between sucrose molecules easier to succeed. The collisions between the water molecules and the sugar molecules are at a high rate due to increased temperature.

4 0
3 years ago
The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be
dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

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