A saturated solution of Ammonium Chloride is dissolved in 100 g of water.
1 answer:
Answer:
10 g
Explanation:
All we need is to read off the solubility curve attached to this answer. The solubility curve is a plot of solubility of a solute against temperature.
By reading off the solubility curve, we can know the mass of precipitate that crystallizes out as the solution is cooled from 50°C to 30°C.
From the solubility curve;
Mass of Ammonium Chloride dissolved at 50°C = 50 g
Mass of Ammonium Chloride dissolve at 30°C = 40 g
Hence;
Mass of precipitate formed = 50 g - 40 g
Mass of precipitate formed = 10 g
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Explanation:
As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.
Hence, calculate the molecular weight of the mixture as follows.
Weight =
= 27.8336 g/mol
And, molar flow rate of air and mixture is calculated as follows.
= 28.74 kmol/hr
Now, applying component balance as follows.
= 43.11 kmol/hr
= 43.11 - 28.74
= 14.37 kmol/hr
So, mass flow rate of pure (B), is =
= 416.73 kg/hr
According to the product stream, 6 mol% A and 94 mol% B is there.
Molecular weight of product stream =
=
= 28.22 g/mol
Mass of product stream = 1216.67 kg/hr
Hence, mole of into the product stream is as follows.
=
= 272.31 kg/hr
Therefore, calculate the mass % of into the stream as follows.
= 22.38%
Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of in the product gas is 22.38%.