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Naily [24]
3 years ago
15

A saturated solution of Ammonium Chloride is dissolved in 100 g of water.

Chemistry
1 answer:
faltersainse [42]3 years ago
5 0

Answer:

10 g

Explanation:

All we need is to read off the solubility curve attached to this answer. The solubility curve is a plot of solubility of a solute against temperature.

By reading off the solubility curve, we can know the mass of precipitate that crystallizes out as the solution is cooled from 50°C to 30°C.

From the solubility curve;

Mass of Ammonium Chloride  dissolved at 50°C = 50 g

Mass of Ammonium Chloride  dissolve at 30°C = 40 g

Hence;

Mass of precipitate formed = 50 g - 40 g

Mass of precipitate formed = 10 g

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12.A piece of magnesium is in the shape of a cylinder with a height of 5.62 cm
yaroslaw [1]

Answer:

Density, d = 1.779 g/cm³

Explanation:

The density of a material is given by its mass per unit volume.

Here, height of a piece of magnesium cylinder, h = 5.62 cm

Its diameter, d = 1.34 cm

Radius = 0.67 cm

Volume of he cylinder,

V=\pi r^2 h\\\\\text{Putting the value of r and h, we get :}\\\\V=(\pi \times (0.67)^2\times 5.62)\ cm^3

d=\dfrac{m}{V}\\\\d=\dfrac{14.1\ g}{(\pi \times (0.67)^2\times 5.62)\ cm^3}\\\\d=1.779\ g/cm^3

So, the density of the sample is 1.779 g/cm³.

4 0
3 years ago
Convert 25.4 grams of barium phosphate, Ba3(PO4)2 to formula units.
Salsk061 [2.6K]
To solve this questions you first need to find the number of moles of barium phosphate you have. The molar mass of barium phosphate is 601.93g/mol.
24.4/601.83 = 0.0402 moles barium phosphate
Then you need to use avagadro’s number, 6.022 x 10^23, which is the number of molecules or formula units in a mole.

6.022 x 10^23 * 0.0402 = 2.42 x 10^22 formula units
7 0
2 years ago
Scienests use critical thinking skills throughout the process of research or experimentation. A student notices than
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Answer:go read ur book and u will find it!!

Explanation:

4 0
3 years ago
(worth 10pts!!!!!!) What did Dmitri Mendeleev contribute to science? A. He arranged the first periodic table. B. He developed th
vesna_86 [32]

Answer:

A. He arranged the first periodic table.

Explanation:

3 0
3 years ago
Read 2 more answers
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
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