A saturated solution of Ammonium Chloride is dissolved in 100 g of water.
1 answer:
Answer:
10 g
Explanation:
All we need is to read off the solubility curve attached to this answer. The solubility curve is a plot of solubility of a solute against temperature.
By reading off the solubility curve, we can know the mass of precipitate that crystallizes out as the solution is cooled from 50°C to 30°C.
From the solubility curve;
Mass of Ammonium Chloride dissolved at 50°C = 50 g
Mass of Ammonium Chloride dissolve at 30°C = 40 g
Hence;
Mass of precipitate formed = 50 g - 40 g
Mass of precipitate formed = 10 g
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Answer:
the Molar heat of Combustion of diphenylacetylene =
Explanation:
Given that:
mass of diphenylacetylene = 0.5297 g
Molar Mass of diphenylacetylene = 178.21 g/mol
Then number of moles of diphenylacetylene =
=
= 0.002972 mol
By applying the law of calorimeter;
Heat liberated by 0.002972 mole of diphenylacetylene = Heat absorbed by
+ Heat absorbed by the calorimeter
Heat liberated by 0.002972 mole of diphenylacetylene = msΔT + cΔT
= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C
= 17756.48 J + 2842.39 J
= 20598.87 J
Heat liberated by 0.002972 mole of diphenylacetylene = 20598.87 J
Heat liberated by 1 mole of diphenylacetylene will be =
= 6930979.139 J/mol
= 6930.98 kJ/mol
Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene =