In a hydrogen bomb, hydrogen is converted into:

Physical or Chemical change: Burning Wood <br> Physical<br> chemical

mrs_skeptik [129]

Answer:

I think physical but I could be wrong

4 0

3 years ago

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Why does a hot air balloon rise when the air inside it is heated

Nastasia [14]

hot air rises up in the balloon and lifts the balloon up

7 0

3 years ago

What is the energy required to remove an electron from an atom in the gaseous state called

KatRina [158]

Answer:

The energy required to remove the the electrons from gaseous atom is called ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from gaseous atom is called ionization energy.

Trend of ionization energy in periodic table:

Along period:

The atomic size tend to decrease in same period of periodic table with increase of atomic number because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Along group:

Atomic size increases with increase of atomic number from top to bottom. The nuclear attraction on valance shell became weaker and thus it becomes easy to remove an electron from valance shell and this can be done with less amount of energy. That's why ionization energy decreases from top to bottom.

4 0

3 years ago

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The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial conce

kipiarov [429]

Answer:

$t=23.5min$

Explanation:

Hello,

In this case, since the rate equation turns out as shown below due to the first-order kinetics:

$\frac{dC_A}{dt}=-kC_A$

Its integration results:

$\int\limits^{C_A}_{C_A^0} { \frac{dC_A}{C_A}} \,=-k\int\limits^t_0 {} \, dt\\ln(\frac{C_A}{C_A^0})=-kt$

However, the rate constant is computed by considering the given half-life time as follows:

$k=\frac{ln(2)}{t_{1/2}}=\frac{ln(2)}{2.42x10^3s}=2.86x10^{-4}s^{-1}$

In such a way, the required time in minutes to diminish the concentration by 66.8% of the initial turns out:

$C_A=0.668C_A^0$

$ln(\frac{0.668C_A^0}{C_A^0})=-kt$

$t=\frac{-ln(0.668)}{2.86x10^{-4}s^1}=1408.3s*\frac{1min}{60s} \\t=23.5min$

Best regards.

3 0

3 years ago

what two effects might occur if most of the phytoplankton living in the world's oceans were destroyed?

klio [65]

Well for one the Oceans food chain starts with the sun and then microscopic organisms such as phytoplankton, and if they were destroyed the fish and other small creatures would eventually die off and then larger animals would too. Then that could lead to not much sea life, or sea food left for other people and animals

8 0

3 years ago

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