Choice D To factor a quadratic equation ax^2+bx+c, find two factors of a and write them in a column, one up, one down. Then find two factors of c and write them in a column. multiply the factors diagonally and add up the products to make b. if the products do not make b, switch the factors up down and try again till you have a match. in this case, -1 and 3 are the factors of -3, -5 and 1 are the factors of -15, -1 times 1 is 1, 3 times -5 is -15, -1 and -15 make a sum of -16. so you have (-1x-5)(3x+1) take the negative sign out you have -(x+5)(3x+1) I hope I've made myself clear.
You have to make them have the same denominator so 1/2=2/4 Then you add them together 2/4+3/4=5/4 You have to make it a mixed fraction. 4 goes into 5 one time and has a remainder of 1 so you get 1 and 1/4?