Question

Calculate work done by the electrostatic force to move the charge with the magnitude of 1nC between two points 2cm spaced, along the equipotential line, corresponding to the potential of 1V

Answer 1

Answer:

work done is = 0

Explanation:

given data

distance = 2 cm

potential = 1 V

charge with magnitude = 1 nC

to find out

work done by the electrostatic force

solution

we know that at equipotential surface is that surface which have equal potential at each every point that we say

work done will be

work done = ∫dw

∫dw = $\int\limits^v1_v2 {q} \, dv$

here q is charge

so

net work done = q ( v2 - v1 )

and

so v2 = v1 = 0

so

work done is = 0