Question

In which set do all elements tend to form anions in binary ionic compounds? li, na, k n, o, i c, s, pb k, fe, br?

Answer 1

Atoms or molecule after gaining of electron possesses negative charge and is known as anion.

For the given sets:

• $Li, Na, K$

The given elements are alkali metals and have tendency to lose electrons easily and form cations.

• $N, O, I$

The given elements are non-metals and are electronegative. So, they gain electrons easily and form anion.

• $C, S, Pb$

Carbon has tendency to form bond by sharing of electrons, Sulfur has tendency to gain electrons and form anion whereas Lead has tendency to lose electron.

• $K, Fe, Br$

Potassium and Iron has tendency to lose electron and form cation whereas Bromine has tendency to gain electron to form anion.

Hence, from the given sets, all elements of set: $N, O, I$ have tendency to form anions in binary ionic compounds.

Answer 2

The elements tend to form anions in binary ionic compounds are elements O, S and I

Further explanation

Ions are atoms that have a charge

Ions are formed because events are capturing or releasing electrons.

Ions can be differentiated based on the number of constituent elements they become

• 1. monatomic ion, if it comes from one element, such as K⁺, Mg²⁺, Cl⁻

• 2. polyatomic ion, if it comes from two or more elements such as PO₄³⁻, SO₄²⁻, ClO₃⁻

Based on the charge, ions can be divided into:

• 1. positive ion (cation)

happens if the atom releases electrons, for example

Al³⁺, ---> Al⇒ Al³⁺ + 3e⁻

Pb²⁺, ----> Pb⇒ Pb²⁺ + 2e-

• 2. negative ion (anion)

happens if the atom captures electrons, like

S²⁻, S + 2e⁻⇒ S²⁻

F⁻, F + e⁻⇒ F⁻

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

Binary ionic compounds are formed from 2 different atomic elements, namely metal and non-metal

From some of these ions

Li, Na, K, N, O, I, C, S, Pb, Fe, Br

• 1. elements Li, Na, K (all three groups IA), Fe (transition group, VIIIB) and Pb (group IVA) are metals that tend to form positive ions (cations)

Li⁺, Na⁺, K⁺, Fe²⁺ / Fe³⁺, Pb²⁺, Pb³⁺

• 2. elements O, S (class VIA), I (class VIIA) are non-metals which tend to form negative ions (anions)

O²⁻, S²⁻, I⁻

• 3. elements C (group IVA) and N (group VA) are non-metals which tend to form polyatomic negative ions (anions)

NO³⁻, NO²⁻, CO₃²⁻, C₂O₄²⁻

So the elements tend to form anions in binary ionic compounds are elements O, S and I

Learn more

The net ionic equation

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ion stability

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ionic bonding

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Keywords: binary ionic compounds, elements, cations, anions, polyatomic, monoatomic