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3 years ago

A cheetah can accelerate at 4.5 m/s from rest to a speed of 30.0 m/s. Calculatethe distance

Physics

1 answer:

anzhelika [568]3 years ago

8 0

Answer:

d= 100m

Explanation:

Cheetah kinematic

The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:

d= v₀*t + (1/2)*a*t² Formula (1)

vf²=v₀²+2*a*d Formula (2)

vf=v₀+a*t Formula (3)

Where:

d:distance in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

t: time in seconds (s)

Known Data

v₀ =0

a = 4.5 m/s²

vf= 30 m/s.

Problem development

We apply the formula (2) that has known data to calculate the distance :

vf²=v₀²+2*a*d

(30)²= 0 + 2* 4.5* d

$d= \frac{900}{9}$

d= 100m

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Answer:

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Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

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Using the equation to find $v_1$ ,

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Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

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$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

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$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

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3 years ago

How many joules of heat must be transferred to a 410-g aluminum pizza pan to raise its temperature from 32oC to 232oC? The speci

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Answer:

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substituting,

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Explanation:

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MissTica

Answer:

True

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