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3 years ago

A cheetah can accelerate at 4.5 m/s from rest to a speed of 30.0 m/s. Calculatethe distance

Physics

1 answer:

anzhelika [568]3 years ago

8 0

Answer:

d= 100m

Explanation:

Cheetah kinematic

The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:

d= v₀*t + (1/2)*a*t² Formula (1)

vf²=v₀²+2*a*d Formula (2)

vf=v₀+a*t Formula (3)

Where:

d:distance in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

t: time in seconds (s)

Known Data

v₀ =0

a = 4.5 m/s²

vf= 30 m/s.

Problem development

We apply the formula (2) that has known data to calculate the distance :

vf²=v₀²+2*a*d

(30)²= 0 + 2* 4.5* d

$d= \frac{900}{9}$

d= 100m

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A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in

miv72 [106K]

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is $\mu_s = 0.60$

The value for static friction is $\mu_k = 0.70$

Explanation:

From the question we are told that

The mass of the clock is $m = 95 \ kg$

The first horizontal force is $F _s = 560 \ N$

The second horizontal force is $F _k = 650 \ N$

Generally the static frictional force is equal to the first horizontal force

$F _s = m * g * \mu_s$

=> $560 = 95 * 9.8 * \mu_s$

=> $\mu_s = 0.60$

Generally the kinetic frictional force is equal to the second horizontal force

$F _k = m * g * \mu_k$

$650 = 95 * 9.8 * \mu_k$

$\mu_k = 0.70$

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3 years ago

A graduated beaker with 375 mL of water is sitting on a scale which measures the weight of the glass and water to be 7.60 N. Whe

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Answer:

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Vr = volume of rock = 75 ml

Wr = 9.22 - 7.60 = 1.62 N weight of 75 ml of rock

Density of rock = 1.62 N / 75 ml = .0216 N / ml

Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml

Density of rock / density of water = .0216 / .0098 = 2.20

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3 years ago

In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves wit

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Given :

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To Find :

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Solution :

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Putting, t = 1 s and x = 4 m in above equation, we get :

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Therefore, the acceleration of the cart is 8 m/s².

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A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

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Answer with Explanation:

We are given that

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