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maxonik [38]
3 years ago
14

A bike travels at a constant speed of 4.0m/s for 5 seconds. How far it goes ?

Physics
2 answers:
Y_Kistochka [10]3 years ago
7 0

Answer:

Distance, d = 20 meters

Explanation:

It is given that,

Speed of the bike, v = 4 m/s

Time taken, t = 5 sec

We need to find the distance covered by the bike during this time. The distance covered by bike is calculated by the product of speed and time

d = v × t

d = 4 × 5

d = 20 meters

So, the bike will go to a distance of 20 meters. Hence, this is the required solution.

alex41 [277]3 years ago
3 0
The speed of 4m/s means that the bike goes 4 meters for each second of movement. Multiplying this by 5 seconds we have a total distance travelled of 20m.
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Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

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