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Dafna11 [192]
2 years ago
8

Two long parallel wires carry currents of 20 a and 5. 0 a in opposite directions. the wires are separated by 0. 20 m. what is th

e magnetic field midway between the two wires? group of answer choices
Physics
1 answer:
kogti [31]2 years ago
3 0

The magnetic field will be given by the formula B=B1+B2.

Between two wires, the magnetic field has the formula B=B1+B2.

We must first calculate the magnetic field caused by each wire before adding the two vectors to find the net magnetic field halfway between the two wires. We must subtract the two vectors in order to find the total magnetic field because the electric current flows in the opposite direction via both cables.

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.

To learn more about the magnetic field please visit -
brainly.com/question/23096032
#SPJ4

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Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter
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We can solve the problem by using the first law of thermodynamics:

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An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
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Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

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speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

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P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

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P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

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Period of brightness variation and luminosity.

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If wave A has twice the amplitude and three times the frequency as wave B, then the energy carried by wave A must be ____ times
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