Two long parallel wires carry currents of 20 a and 5. 0 a in opposite directions. the wires are separated by 0. 20 m. what is th
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Answer: F = 776.18N θ = 29.41°
Question:
The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.
Attached is the image.
Explanation:
To solve this question we need to resolve the forces to the x and y axis.
For the x axis;
Fcosθ = 700cos15....1
For the y axis;
200 = Fsinθ - 700sin15
Fsinθ = 200 + 700sin15 ...2
Dividing equation 2 by 1
Fsinθ/Fcosθ = (200 + 700sin15)/700cos15
Tanθ = (200 + 700sin15)/700cos15
θ = Taninverse(200 + 700sin15)/700cos15)
θ = 29.41°
From equation 1;
F = 700cos15/cosθ
F = 700cos15/cos29.41
F = 776.18N
