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Dafna11 [192]
2 years ago
8

Two long parallel wires carry currents of 20 a and 5. 0 a in opposite directions. the wires are separated by 0. 20 m. what is th

e magnetic field midway between the two wires? group of answer choices
Physics
1 answer:
kogti [31]2 years ago
3 0

The magnetic field will be given by the formula B=B1+B2.

Between two wires, the magnetic field has the formula B=B1+B2.

We must first calculate the magnetic field caused by each wire before adding the two vectors to find the net magnetic field halfway between the two wires. We must subtract the two vectors in order to find the total magnetic field because the electric current flows in the opposite direction via both cables.

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.

To learn more about the magnetic field please visit -
brainly.com/question/23096032
#SPJ4

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At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2. A fan is 30 m from the loudspeak
aliina [53]

Explanation:

Below is an attachment containing the solution.

5 0
3 years ago
All of these are types of electromagnetic waves except for:
dimaraw [331]
C- Sigma Waves, This is what my teacher used to get us to remember https://www.youtube.com/watch?v=bjOGNVH3D4Y
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3 years ago
The work function for tungsten metal is 4.52eV a. What is the cutoff (threshold) wavelength for tungsten? b. What is the maximum
Tanya [424]

Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:

h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.

In order to calculate the cutoff wavelength we have to consider that Ek=0

in this case  h*ν=W

(h*c)/λ=4.52 eV

λ= (h*c)/4.52 eV

λ= (1240 eV*nm)/(4.52 eV)=274.34 nm

From this h*ν = Ek+W;  we can calculate the kinetic energy for a radiation wavelength of 198 nm

then we have

(h*c)/(λ)-W= Ek

Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV

Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

5 0
3 years ago
7. How many 1.00 µF capacitors must be connected in parallel to store a charge of 1.00 C with a potential of 110 V across the ca
Misha Larkins [42]

Answer:

q = C V    charge on 1 capacitor

q = 1 * 10E-6 * 110 = 1.1 *  10E-4  C per capacitor

N = Q / q = 1 / 1.1 * 10E-4  = 9091 capacitors

8 0
3 years ago
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical
MaRussiya [10]

The coefficients in order are 2, 1, 1

<h3>What is balanced chemical equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.

In other words, the mass and the charge are balanced on both sides of the reaction.

According to the given situation,

To balance the the chemical equation,

Step 1 - Add a 2 on the Na2HPO4:

2(Na₂HPO₄)  ⇒ Na4P₂O₇ + H₂O

Step 2 -Next take count of each element on both sides to see if the 2 is balanced or not:

On the left there are 4 Na, 2 H, 2 P, and 8 O

On the right there are 4 Na, 2 H, 2 P, and 8 O

Step 3 - Now we will divide by 2

i.e. 2 NA.H. P

The coefficient of  Na is 2 , Coefficient of H is 1 and Coefficient of P is 1

Therefore,

The coefficients in order are 2, 1, 1.

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8 0
2 years ago
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