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viva [34]
3 years ago
10

The normal body temperature of a camel is 37°C. This temperature varies by up to 3°C throughout the day. Write and solve an abso

lute value inequality that represents the range of normal body temperatures (in degrees Celsius) of a camel throughout the day.
Mathematics
1 answer:
uysha [10]3 years ago
8 0

The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3     AND  ( - t - 37 ) ≤ 3
t ≤ 3 + 37               - t + 37 ≤ 3
t ≤ 40                     - t ≤ 3 - 37
                              - t ≤ - 34   / *( - 1 )
                                t ≥ 34
Answer t <span>∈ [</span><span>  34</span><span>°C,</span><span>  40</span><span>° C ]</span>.

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Find the missing side length. Leave your answer in simplest radical form.
exis [7]

Answer:

4√3

Step-by-step explanation:

For isosoles triangles the legs are congruent

v = u

--------------------

using the pythagorean theorem

(4√6)² = v² + v²

(16 * 6) = 2v²

Divide both sides by 2

16 * 3 = v²

Take the square root of both sides

4√3 = v

6 0
3 years ago
What is the midpoint of AB?
dem82 [27]

It looks like Point G is correct

3 0
3 years ago
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
Do i solve this?? need help???
Arlecino [84]
A =
5 and -5
-1 and 3

¹/₃B =

-6 and 12
-7 and 7

¹/₃B + A =

-1 and 7
-8 and 10
7 0
3 years ago
I need help or I will faill this
kari74 [83]

Answer:

-4x2 + 3x - 225

 ———————————————

        3    

Step-by-step explanation:

Step  1  :

               4

Simplify   —

                3

Equation at the end of step  1  :

        4            

 (x -  (— • x2)) -  75

        3            

Step  2  :

Equation at the end of step  2  :

       4x2      

 (x -  ———) -  75

        3      

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

         x     x • 3

    x =  —  =  —————

         1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • 3 - (4x2)     3x - 4x2

—————————————  =  ————————

      3              3    

Equation at the end of step  3  :

 (3x - 4x2)    

 —————————— -  75

     3          

Step  4  :

Rewriting the whole as an Equivalent Fraction :

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         75     75 • 3

   75 =  ——  =  ——————

         1        3    

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  3x - 4x2  =   -x • (4x - 3)  

Adding fractions that have a common denominator :

5.2       Adding up the two equivalent fractions

-x • (4x-3) - (75 • 3)     -4x2 + 3x - 225

——————————————————————  =  ———————————————

          3                       3        

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  -4x2 + 3x - 225  =   -1 • (4x2 - 3x + 225)  

Trying to factor by splitting the middle term

6.2     Factoring  4x2 - 3x + 225  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  -3x  its coefficient is  -3 .

The last term, "the constant", is  +225  

Step-1 : Multiply the coefficient of the first term by the constant   4 • 225 = 900  

Step-2 : Find two factors of  900  whose sum equals the coefficient of the middle term, which is   -3 .

     -900    +    -1    =    -901  

     -450    +    -2    =    -452  

     -300    +    -3    =    -303  

     -225    +    -4    =    -229  

     -180    +    -5    =    -185  

     -150    +    -6    =    -156  

For tidiness, printing of 48 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

 -4x2 + 3x - 225

 ———————————————

        3        

7 0
3 years ago
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