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slamgirl [31]
3 years ago
5

How many moles of tungsten (W,183.85 g/lol are in 415 grams of tungsten?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
7 0

Given mass of tungsten, W = 415 g

Molar mass of tungsten, W = 183.85 g/mol

Calculating moles of tungsten from mass and molar mass:

415 g * \frac{1 mol}{183.85 g} = 2.26 mol W

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Plz help, have a quiz on this plz PLZ
katovenus [111]

Answer:

20.82

Explanation:

7 0
3 years ago
One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?
gizmo_the_mogwai [7]
27*9=243 if one mole is equal to 27 grams times that by 9
6 0
3 years ago
A solution is prepared by dissolving 106.3 g HCl(g) in enough water to make 175.0 L of solution. The ph of this solution is
DedPeter [7]

Answer:

moles HCl = 101.2 g /36.461 g/mol=2.78

[H+]= 2.78 mol/ 150 L =0.0185

pH = - log 0.0185=1.73

1.73 is the answer

3 0
3 years ago
Which area of the periodic table has the highest electronegatvities
krok68 [10]

The area where the periodic table has the highest electronegativity are Groups 1 and Groups 7 because they are close on giving away an electron and the other is close to becoming stable.  

8 0
3 years ago
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
3 years ago
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