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Lorico [155]
3 years ago
8

Dante wrote several equations and determined that only one of the equations has infinitely many solutions. Which of these equati

ons has infinitely many solutions?
A.6(x+3)+x=7x+2+1
B.6(x+3)+x=7x+5
C.6(x+3)+x=6x+3+15
D.6(x+3)+x=7x+9+9
Mathematics
2 answers:
ss7ja [257]3 years ago
5 0

Answer:

D; 6(x  + 3) + x = 7x + 9 + 9

Step-by-step explanation:

6x + 18 + x = 7x + 9 + 9

7x + 18 = 7x + 18

The equation has equivalent coefficients and constants on both sides, which proves that it has infinitely many solutions.

____ [38]3 years ago
3 0
The answer is D I believe
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Which of the following describes the end behavior over the domain of the square root function graphed above? Please HELP!!!!!!!!
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Short Answer A
Comment

It's a good thing that the domain is confined or the graph is. That function is undefined if x < - 3 

At exactly x = - 3, f(x) = 0 and that's your starting point.

So look what happens to this graph. If x = 0, f(0) =  y = 3. So we are starting to see that as x get's larger so does f(x). The graph tells us that x = 0 is bigger than x = - 3.

Let's keep on plugging things in.
As x increases to 5, f(5) = 5. x = 5 is larger than x = 0, and f(5) > 3.

One more and then we'll start drawing conclusions. If x = 9 then f(9) = y =  6. 
x = 9 is larger than x = 5. f(9) = 6 is just larger than f(5) which is 5

OK I think we should be ready to look at answers. There's nothing there that makes the answer anything but a. Let's find out what the problem is with the rest of the choices.

B
The problem with B is that as x increases, f(x) does not decrease. We didn't find one example of that. So B is wrong.

C
C has exactly the same problem as B. 

D
The second statement in D is incorrect. As x increases f(x) never decreases. No example showed that.

The answer is A <<<< Answer.
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