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Lorico [155]
2 years ago
8

Dante wrote several equations and determined that only one of the equations has infinitely many solutions. Which of these equati

ons has infinitely many solutions?
A.6(x+3)+x=7x+2+1
B.6(x+3)+x=7x+5
C.6(x+3)+x=6x+3+15
D.6(x+3)+x=7x+9+9
Mathematics
2 answers:
ss7ja [257]2 years ago
5 0

Answer:

D; 6(x  + 3) + x = 7x + 9 + 9

Step-by-step explanation:

6x + 18 + x = 7x + 9 + 9

7x + 18 = 7x + 18

The equation has equivalent coefficients and constants on both sides, which proves that it has infinitely many solutions.

____ [38]2 years ago
3 0
The answer is D I believe
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3 0
3 years ago
Question 2(Multiple Choice Worth 1 points)
Tomtit [17]

The sequence is " Algebraic, common difference = −10 " ⇒ 1st answer

Step-by-step explanation:

Let us revise the algebraic and geometric sequences

  • The Algebraic sequence is the sequence that has a common difference between each two consecutive terms, like 2 , 5 , 8 , 11 , 14 , .......... the difference between the 5 and 2 is equal to the difference between 8 and 5, and the difference between 11 and 8 and the difference between 14 and 11
  • The geometric sequences is the sequence that has a common ratio between each two consecutive terms, like 3 , -9 , 27 , -81 , ...... the ratio between -9 and 3 as the ratio between 27 and -9 as the ratio between -81 and 27

→  x   :    1    :    2    :    3    :    4

→ f(x) :    5   :   -5    :    -15  :    -25

x represents the positions of the terms

f(x) represents the value of each term

∵ 1st = 5 and 2nd = -5

∵ -5 - 5 = -10

∵ 2nd = -5 and 3rd = -15

∵ -15 - (-5) = -15 + 5 = -10

∵ 3rd = -15 and 4th = -25

∵ -25 - (-15) = -25 + 15 = -10

∴ There is a common difference -10 between each two

   consecutive terms

∴ The sequence is algebraic with common difference -10

The sequence is " Algebraic, common difference = −10 "

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

#LearnwithBrainly

8 0
3 years ago
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