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Lorico [155]
3 years ago
8

Dante wrote several equations and determined that only one of the equations has infinitely many solutions. Which of these equati

ons has infinitely many solutions?
A.6(x+3)+x=7x+2+1
B.6(x+3)+x=7x+5
C.6(x+3)+x=6x+3+15
D.6(x+3)+x=7x+9+9
Mathematics
2 answers:
ss7ja [257]3 years ago
5 0

Answer:

D; 6(x  + 3) + x = 7x + 9 + 9

Step-by-step explanation:

6x + 18 + x = 7x + 9 + 9

7x + 18 = 7x + 18

The equation has equivalent coefficients and constants on both sides, which proves that it has infinitely many solutions.

____ [38]3 years ago
3 0
The answer is D I believe
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4 0
3 years ago
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Step-by-step explanation:

Expand.

32−8x=7x+2

Add 8x to both sides.

32=7x+2+8x

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Subtract 22 from both sides.

32−2=15x

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IgorC [24]

Answer:

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Step-by-step explanation:

The way I like to do it is to get rid of the x's and just use the numbers in the case of synthetic division

Pretend the square root of the division symbol

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Quick note: We're dividing by -4 because we're dividing by x + 4

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Multiply it by 4 then bring add it to the next number

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Add that number to the next one

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Finally repeat the step for the last number

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Now take those bottom numbers and add back the x's but with one less power, so the starting x³ would now become x², x² would become x, and so on

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