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Margarita [4]
3 years ago
7

What is the missing product 4, 6, 9, 14, ?, 49

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0
I think it's 35, because 49-14=35
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Please answer this if you solve it correctly! Thanks (:
OlgaM077 [116]

Hey!

----------------------------------------------

Solution:

= x^2 + 3 / x - 1

= x^2 + \frac{3}{x} - 1

----------------------------------------------

Answer:

= \frac{x^3 - x + 3}{x}

----------------------------------------------

Hope This Helped! Good Luck!

5 0
3 years ago
Help pls 9 through 11
In-s [12.5K]

Step-by-step explanation:

the coordinate for P is (-3,6)

5 0
3 years ago
At the same time of day, a man who is 75 inches tall casts a 50-inch shadow and his son casts a 22-inch shadow. What is the son'
nikitadnepr [17]

Answer: i think its 55 but im not sure

8 0
3 years ago
Read 2 more answers
Solve the system by finding the reduced row-echelon form of the augmented matrix.
Alex

Answer:

The reduced row-echelon form is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The solutions to the system of equations are:

y=-2z-3,\:x=-6z-10

Step-by-step explanation:

To solve this system of linear equations,

x-4y-2z=2\\2x-11y-10z=13\\-x+6y+6z=-8

you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is the augmented matrix that represents the system.

\left[ \begin{array}{cccc} 1 & -4 & -2 & 2 \\\\ 2 & -11 & -10 & 13 \\\\ -1 & 6 & 6 & -8 \end{array} \right]

It can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

  1. Interchange two rows (or columns).
  2. Multiply each element in a row (or column) by a non-zero number.
  3. Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: add -2 times the 1st row to the 2nd row

Row Operation 2: add 1 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1/3

Row Operation 4: add -2 times the 2nd row to the 3rd row

Row Operation 5: add 4 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

x+6z=-10\\y+2z=-3\\0=0

The system has infinitely many solutions.

y=-2z-3,\:x=-6z-10

4 0
4 years ago
The graph of a quadratic function is shown.
saul85 [17]

Answer:

B) Vertex: (–9,2); minimum

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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