Answer:
The intermediate is carbocation.
Explanation:
The reaction of alkene with an acid to give alcohol is an electrophilic addition reaction.
In electrophilic reaction, the alkene is being attacked by an alkene.
in case of aqueous acid reaction with alkene , the electrophile is [H⁺].
When the proton attacks the alkene it generates carbocation.
The carbocation generated is formed based on stability of carbocation.
The mechanism is shown in the figure.
Answer:
Normally, it explains that matter cannot be created or destroyed. It demonstrates different chemical reactions that help show the different transformations of the matter but will never destroy it or create it.
Answer:
PN₂ = 191.3 Kpa
Explanation:
Given data:
Total pressure of tire = 245.0 Kpa
Partial pressure of PO₂ = 51.3 Kpa
Partial pressure of PCO₂ = 0.10 Kpa
Partial pressure of others = 2.3 Kpa
Partial pressure of PN₂ = ?
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = PO₂ + PCO₂ + P(others)+ PN₂
245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂
245 Kpa = 53.7 Kpa+ PN₂
PN₂ = 245 Kpa - 53.7 Kpa
PN₂ = 191.3 Kpa
Answer:
Substances can change phase—often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous.
The process of a solid becoming a liquid is called melting. (an older term that you may see sometimes is fusion). The opposite process, a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance. It requires energy for a solid to melt into a liquid. Every pure substance has a certain amount of energy it needs to change from a solid to a liquid. This amount is called the enthalpy of fusion (or heat of fusion) of the substance, represented as ΔHfus. Some ΔHfus values are listed in Table 10.2 “Enthalpies of Fusion for Various Substances”; it is assumed that these values are for the melting point of the substance. Note that the unit of ΔHfus is kilojoules per mole, so we need to know the quantity of material to know how much energy is involved. The ΔHfus is always tabulated as a positive number. However, it can be used for both the melting and the solidification processes as long as you keep in mind that melting is always endothermic (so ΔH will be positive), while solidification is always exothermic (so ΔH will be negative).
Table 10.2 Enthalpies of Fusion for Various Substances
Explanation:
