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3 years ago

Convert 121 Cal to kilowatt-hours

Chemistry

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

here

Explanation:

0.000141 to kilowatt-hours. hope this helped

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A 4 L sample of gas at 298 K and 2 atm contains 0.250 mol of gas. If we add another 0.250 mol of gas at the same pressure and te

andrey2020 [161]

Answer:

$V_2=8L$

Explanation:

Hello there!

In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Which can be solved for the final volume, V2, as shown below:

$V_2=\frac{V_1n_2}{n_1}$

Thus, by plugging in the given data, we obtain:

$V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L$

Regards!

4 0

3 years ago

Write the balanced chemical equation for each of these reactions. Include phases.

Ket [755]

Answer: The chemical equations are given below.

Explanation:

For 1:

The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:

$Pb(NO_3)_2(aq.)+2NaOH(aq.)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq.)$

By Stoichiometry of the reaction:

1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.

For 2:

The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:

$Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)$

By Stoichiometry of the reaction:

1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex

Hence, the chemical equations are given above.

4 0

3 years ago

Calculate the theoretical yield in moles of magnesium chloride when 37 grams of Mg(s) react with 38 grams of HCl(aq).Write the a

goblinko [34]

Answer:

The correct answer is 0.52 moles.

Explanation:

Based on the given question, 37 grams of magnesium reacts with 38 grams of HCl to produce MgCl2 or magnesium chloride. The reaction is:

Mg (s) + 2HCl (aq) ⇒ MgCl2 (aq) + H2 (g)

There is a need to find the theoretical yield in moles of MgCl2. The formula for calculating the no. or moles is mass/molar mass. Therefore, moles of magnesium is 37/24 = 1.54 and moles of HCl will be 38/36.5 = 1.04.

From the reaction it is clear that one mole of magnesium reacts with two moles of HCl, as lesser quantity of HCl is present in the given case, therefore, HCl will be the limiting reagent.

Now theoretical moles of magnesium chloride will be,

= moles of HCl / 2

= 1.04 / 2

= 0.52 moles

6 0

3 years ago

Which factor is defined as the average kinetic energy of a substance?

AveGali [126]

A. mass of the substance

4 0

4 years ago

6. What does the symbol AH stand for?

Vesnalui [34]

the heat of reaction for a chemical reaction

4 0

4 years ago