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finlep [7]
2 years ago
10

The amount of gram - atoms in two gramm of sulfur is (NB: S=32amu)​

Chemistry
1 answer:
stiv31 [10]2 years ago
6 0

Answer:

3.76375e+22

Explanation:

(2/32)×(6.022 × 10^23)

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What happens to the energy added during a phase change?
Ivanshal [37]

Answer:You're answer is D: it is converted to kinetic energy

Explanation:

During a change of phase, the average kinetic energy of the molecules stays the same, but the average potential energy changes. ... My interpretation is that during a phase change, the temperature remains equal, but the kinetic energy of its particles increase/decrease.

                                             LINK:

https://chemistry.stackexchange.com/questions/82163/clarification-of-kinetic-energy-during-phase-change

7 0
4 years ago
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What energy is required to remove the remaining electron from singly ionized helium?
skelet666 [1.2K]

To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.

The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.

Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .

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3 0
1 year ago
A 2.0-liter aqueous solution contains a total of 3.0 moles of dissolved NH4Cl at 25°C and standard pressure.
vladimir1956 [14]
The molarity is a concentration unit which defined as the number of moles of solute divided by the number of liters of solution. So the molarity of the solution is 3/2=1.5 mol/L.
7 0
3 years ago
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Which solution has the highest boiling point at standard pressure?
julia-pushkina [17]
Pressure: when the external pressure is:
less than one atmosphere, the boiling point of the liquid is lower than its normal boiling point.
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8 0
3 years ago
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How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
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