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vfiekz [6]
3 years ago
11

A carton has a length of 2 2/3, width of 1 1/3, and height of 1 1/2 feet. What is the volume of the carton?

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0
I hope this helps you

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Please help me with this i really dont get what it means, thank you!! xo
Tasya [4]

i would probably say the first option. you basically want to use the 2 points that are outside of the majority of all of the other points. in this case, i am pretty sure it would be the first option. i am not 100% sure, but i think that's the correct answer :)

5 0
3 years ago
Which expression shows how 6 • 45 can be rewritten using the distributive property?
tatuchka [14]
6*45=270 is the first step you should do to get the answer you are looking for. The next thing I would do is go to all the answers to see which one comes out the same way. The first one comes to be 246, the next one is 54, the next is 270 and the last one is 220. 6*40+6*5 is the correct answer.

4 0
3 years ago
48 L = ____ ML steps plz
Oliga [24]

Ok there are 48000 mL in 48L.

7 0
3 years ago
What is the value of x for which m || n?<br> x = 40<br> x = 5<br> x = 105<br> x = 30
QveST [7]

Answer:

(A) x=40

Step-by-step explanation:

Given: It is given that m is parallel to n.

To find: The value of x.

Proof: It is given that m is parallel to n, from the figure it can be seen that 105° and (3x-15)° forms alternate exterior angles which are equal in measure because m is parallel to n.

Thus, 105^{\circ}=3x-15^{\circ}

⇒105^{\circ}+15^{\circ}=3x

⇒120^{\circ}=3x

⇒\frac{120}{3}=x

⇒x=40

Thus, the value of x is 40, hence option A is correct.

4 0
3 years ago
Read 2 more answers
Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}

In the second equation, we have

xr^3-xr=xr(r^2-1)=36

and in the first, we have

xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32

Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

4 0
3 years ago
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