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3 years ago

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A spring with a spring constant value of 2500 StartFraction N over m EndFraction is compressed 32 cm. A 1.5-kg rock is placed on

top of it, then the spring is released. Approximately how high will the rock rise? 9 m 17 m 27 m 85 m

2 answers:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

9m

Explanation:

edge2o2o

Sedaia [141]3 years ago

5 0

Answer:

it's 9m

Explanation:

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Tell the difference between an internal and an external influence and give 1 examples of each.

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The natural pH of rain water is?

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3 years ago

Read 2 more answers

person holds a 0.300 kg pomegranate at the top of a tower that is 96 m high Another person holds a 0.800 kg melon next to an ope

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Well, for one thing, it could depend on which fruit is dropped first. You haven't mentioned that.

If they're both dropped at exactly the same time, then the melon at 32m hits the ground first.

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3 years ago

Consider an airplane with a wing area of 240 ft2 , a span of 44 ft, an Oswald efficiency of 0.75, and a zero-lift drag coefficie

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4 years ago

How do we solve questions C and D? I already did A and B and I am confused on how to continue

aleksandrvk [35]

(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.

(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.

<h3>Work done in moving the charge from C to A</h3>

W = Fd

W = Kq²/d

from 0 origin to C, d = √(5² + 5²) = 7.07 m
from 0 origin to A, d = 5 m

W(C to A) = W(0 to C) + W(0 to A)

$W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A) = 0.0586 \ Kq^2\\\\W(C \ to \ A) = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A) = 7.62 \times 10^{-3} \ J$

<h3>Work done in moving the charge from D to B</h3>

from 0 origin to D, d = √(5² + 5²) = 7.07 m
from 0 origin to B, d = 5 m

W(D to B) = W(0 to D) + W(0 to B)

W(D to B) = 7.62 x 10⁻³ J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

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2 years ago