The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by
where,
Since, T=37+273 K = 310 K
v = 331 m/s
Using this, we get:
Hence, the fundamental frequency is 367.42 Hz.
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Answer:
linear charge density = -9.495 × C/m
Explanation:
given data
revolutions per second = 1.80 ×
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 × ×
q = m × w² × r ............2
and w =
w =
w = 1.80 × ×
w = 11304000 rad/s
so here from equation 2
- 9 × ×
1.80 ×
= 1.672 ×
× 11304000² × 0.0120
linear charge density = -9.495 × C/m