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solmaris [256]
3 years ago
13

A spring with a spring constant value of 2500 StartFraction N over m EndFraction is compressed 32 cm. A 1.5-kg rock is placed on

top of it, then the spring is released. Approximately how high will the rock rise? 9 m 17 m 27 m 85 m
Physics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

9m

Explanation:

edge2o2o

Sedaia [141]3 years ago
5 0

Answer:

it's 9m

Explanation:

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Which statement describes the effects of forces on an object
lukranit [14]

Answer:

Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.

Explanation:

8 0
3 years ago
A net force applied to a 15.0 kg box produced an acceleration of 4.2 m/s2. If the same net force was applied to a 10 kg box, wha
igor_vitrenko [27]

Answer:

6.3\ m/s^2

Explanation:

Given that,

If the mass of a body is 15 kg and produced an 4.2 m/s², we need to find the acceleration if the mass is 10 kg and the same force is applied.

Force is given by :

F = ma

Since force is same

m_1a_1=m_2a_2\\\\a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{15\times 4.2}{10}\\\\a=6.3\ m/s^2

So, if the mass is 10 kg, acceleration is 6.3\ m/s^2

8 0
3 years ago
How are motion and acceleration alike? How are they different?
ratelena [41]

Answer:

Motion is the action of moving, and acceleration is the action of moving faster or increasing speed. I guess you could say they are both in a state of motion or moving.

Explanation:

4 0
3 years ago
6th grade science !!!!!!!!!!!!!!​
mrs_skeptik [129]
Answer: B
Explanation: I hope this helps you
8 0
3 years ago
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An ac generator has a frequency of 5.0 kHz and a voltage of 45 V. When an inductor is connected between the terminals of this ge
Ierofanga [76]

Answer:

Explanation:

Given that,

Frequency f = 5 kHz = 5000Hz

Voltage V=45V

Current In inductor I = 65mA

I = 65 × 10^-3 = 0.065A

We want to find inductance L

We know that the reactive inductance cam be given as

XL = 2πFL

Where

XL is reactive inductance

F is frequency

L is inductance

Then,

L = XL/2πF

From ohms law

V = IR

We can calculate the receive reactance of the inductor

V = I•XL

Then, XL = V/I

XL = 45/0.065

XL = 692.31 ohms

Then,

L = XL/2πF

L = 692.31/(2π×5000)

L = 0.02204 H

Then, L = 22.04 mH

The inductance of the inductor is 22.04mH

4 0
3 years ago
Read 2 more answers
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