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3 years ago

Which of the following would affect the climate of an area?

Physics

2 answers:

Fofino [41]3 years ago

8 0

I believe it would be a hot day in January, because deer like the cold. So if the snow melted and it would be really hot like summer, it would affect deer and other animal life.

The way it'd affect the climate is it could possibly affect snow. Maybe the next couple of days or weeks would be hot and when it is starting to get colder, it could not snow again for a long or short period of time

Yuliya22 [10]3 years ago

5 0

ΒγΕ the answer should be a hot day

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A 234.0 g piece of lead is heated to 86.0oC and then dropped into a calorimeter containing 611.0 g of water that initally is at

Vaselesa [24]

Answer: $24.70 ^{\circ}C$

Explanation:

Given

mass of lead piece $m_l=234 gm\approx 0.234 kg$

mass of water in calorimeter $m_w=611 gm\approx 0.611 kg$

Initial temperature of water $T_w=24^{\circ}C$

Initial temperature of lead piece $T_l=24^{\circ}C$

we know heat capacity of lead and water are $125.604 J/kg-k$ and $4.184 kJ/kg-k$ respectively

Let us take $T ^{\circ}C$ be the final temperature of the system

Conserving energy

heat lost by lead=heat gained by water

$m_lc_l(T_l-T)=m_wc_w(T-T_w)$

$0.234\times 125.604(86-T)=0.611\times 4.184\times 1000(T-24)$

$86-T=\frac{0.611\times 4.184\times 1000}{29.391}(T-24)$

$86-T=86.97T-2087.49$

$T=\frac{2173.491}{87.97}=24.70^{\circ}C$

3 0

2 years ago

How will the boat be affected if it enters a part of the river where the current is moving south at 2 m/s?

Paladinen [302]

Answer:

the boat will either break or go alot faster

Explanation:

3 0

3 years ago

Read 2 more answers

What do you do if you approach a railroad crossing with a crossbuck sign that has no lights or gates

miv72 [106K]

Proceed with caution before crossing

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3 years ago

Unpolarized light of intensity I=10 falls on two successive polarizer wheels with the angle between the polarizer wheels e-60°.

yan [13]

Answer:

$I=\frac{10}{4}$

Explanation:

A polarizer changes the orientation of the oscillations of a light wave.

I₀ = Intensity of unpolarized light = 10

θ = Angle given to the polarizer = 60°

Intensity of light

I = I₀cos²θ

⇒I = 10cos²60

$\\\Rightarrow I=10\times \frac{1}{2}\times \frac{1}{2}\\\Rightarrow I=\frac{10}{4}$

So, the after passing through the second polarizer is $\mathbf{\frac{10}{4}}$

5 0

3 years ago

A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 meter distance by applying a brake. No

kozerog [31]

Answer: $-2502N$

Explanation:

$(V_2)^2=(V_1)^2+2ad$

where;

$V_2$ = final velocity = 0

$V_1$ = initial velocity = 60 km/h = 16.67 m/s

$a$ = acceleration

$d$ = distance

First all of, because acceleration is given in m/s and not km/h, you need to convert 60km/h to m/s. Our conversion factors here are 1km = 1000m and 1h = 3600s

$60km/h(\frac{1000m}{1km} )(\frac{1h}{3600s} )=16.67m/s$