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coldgirl [10]
3 years ago
8

Help please!!!!!!!!!!

Physics
1 answer:
Juliette [100K]3 years ago
8 0
It's C because no mass is lost or gained in heating and also lava doesn't burn into smoke, like at all.
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ECONOMICS !!!!
gulaghasi [49]

Answer:

B

Explanation:

Absolute advantage is the capability of a commercial entity to produce goods using fewer resources compared to rivals. Using the same inputs, an entity with an absolute advantage produces a larger output compared to competitors. It means the firm has a lower marginal cost of production. Therefore, its products will have the lowest prices in the market.  

6 0
2 years ago
Why are renewable energy resources going to be important in our future
marshall27 [118]
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I hope this helped! :-)
3 0
3 years ago
If an object were released in space far away from planted or stars and given an initial momentum, describe what would happen to
mamaluj [8]
Strange as it may seem, the object would keep moving, in a straight line and at the same speed, until it came near another object. Its momentum and kinetic energy would never change. It might continue like that for a billion years or more.

Have a look at Newton's first law of motion.
7 0
3 years ago
Read 2 more answers
The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Dete
oksian1 [2.3K]

Answer:

The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

The shear stress at a distance 0.5-in away from the pipe wall is 0

Explanation:

Given;

pressure drop per unit length of pipe = 0.6 psi/ft

length of the pipe = 12 feet

diameter of the pipe = 1 -in

Pressure drop per unit length in a circular pipe is given as;

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\

make shear stress (τ) the subject of the formula

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}

Where;

τ is the shear stress on the pipe wall.

ΔP is the pressure drop

L is the length of the pipe

r is the distance from the pipe wall

Part (a) shear stress at a distance of  0.3-in away from the pipe wall

Radius of the pipe = 0.5 -in

r = 0.5 - 0.3 = 0.2-in = 0.0167 ft

ΔP = 0.6 psi/ft

ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2

Part (b) shear stress at a distance of  0.5-in away from the pipe wall

r = 0.5 - 0.5 = 0

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0}{2*12} =0

3 0
3 years ago
What will happen if we put a magnet in cold water
gayaneshka [121]

Answer:

cold water strengthens the magnetic attractive force.

Explanation:

The molecules within the magnet will move slower because they have less kinetic energy,so there is less vibration within the magnets molecules.

8 0
2 years ago
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