A loop of wire carries a conventional current of 0.9 amperes. The radius of the loop is 0.05 m. Calculate the magnitude of the m
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Answer:
The volume of water that was in the kettle is 1170
Explanation:
Given:
Power, P = 2.0 kW = 2000 W, Mass of stainless steel, = 710 g = 0.71 kg at temperature of
Part A:
If it takes time, t = 3.5 minutes to reach boiling point of water , then from conservation of energy,
Total energy supplied by the burner = Total heat gained by the water and the stainless steel to rise from to
i.e. Pt = (100 - 20 ) +
(100 - 20 )
=
= 1.17 kg
where = 4200 J/Kgk (specific heat capacity of water),
= 450 J/Kgk (specific heat capacity of steel)
But volume of water in the the kettle, v =
∴ v = 1170
Answer:
Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s
Explanation:
Given Data:
V is the overall velocity vector, and
are its initial vertical and horizontal components
To find:
Max Height achieved
Calculation:
1) Using the equation of motion, we know
2) In terms of gravity height
and the vertical component of Velocity
.
3) As as at maximum height the vertical component of velocity is zero maximum height achieved
putting values
4)
5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)