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USPshnik [31]
3 years ago
14

A loop of wire carries a conventional current of 0.9 amperes. The radius of the loop is 0.05 m. Calculate the magnitude of the m

agnetic field at a distance of 0.46 m along the axis of the loop, from the center of the loop. B
Physics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

0.098 T

Explanation:

Parameters given:

Current in the wire, I = 0.9 A

Radius of loop, r = 0.05 m

Distance of the point of consideration, L = 0.46 m

The magnetic field, B, at distance, L, due to a current, I, flowing in a wire of radius, r, is given as:

B = (N*r*I) / L

Where N = number of turns in the loop = 1

Therefore, B is:

B = (1 * 0.05 * 0.9) / 0.46

B = 0.098 T

The magnetic field, B is 0.098 T

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Maya and Kenzie are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spil
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The correct answer is A.

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The density of air is 1.3 kg/m^3. What mass of air is contained in a room measuring 2.5m x 4m x 10m? Give your answer in kg. Bra
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4 years ago
An AC power source has an rms voltage of 120 V and operates at a frequency of 60.0 Hz. If a purely inductive circuit is made fro
Dmitrij [34]

Answer:

(a) 17634.24 Ω

(b) 0.0068 A

Explanation:

(a)

The formula for inductive inductance is given as

X' = 2πFL................... Equation 1

Where X' = inductive reactance, F = frequency, L = inductance

Given: F = 60 Hz, L = 46.8 H, π = 3.14

Substitute into equation 1

X' = 2(3.14)(60)(46.8)

X' = 17634.24 Ω

(b)

From Ohm's law,

Vrms = X'Irms

Where Vrms = Rms Voltage, Irms = rms Current.

make Irms the subject of the equation

Irms = Vrms/X'...................... Equation 2

Given: Vrms = 120 V, X' = 17634.24 Ω

Substitute into equation 2

Irms = 120/17634.24

Irms = 0.0068 A

5 0
3 years ago
In a science museum, a 140 kg brass pendulum bob swings at the end of a 16.8 m -long wire.
Mice21 [21]

The period of the pendulum is 8.2 s

Explanation:

The period of a simple pendulum is given by the equation:

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

T is the period

We notice that the period of a pendulum does not depend at all on its mass, but only on its length.

For the pendulum in this problem, we have

L = 16.8 m

and

g=9.8 m/s^2 (acceleration of gravity)

Therefore the period of this pendulum is

T=2\pi \sqrt{\frac{16.8}{9.8}}=8.2 s

#LearnWithBrainly

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3 years ago
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