Question

What is one to one and how do i solve this in steps?

Answer 1

$f(x) = \dfrac{7}{x+2}$

$y = \dfrac{7}{x+2}$

$y(x + 2) = 7$

$xy + 2y = 7$

$xy = 7 - 2y$

$x = \dfrac{7 - 2y}{y}$

$f^{-1}(x) = \dfrac{7 - 2x}{x}$