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4 years ago

PLEASE HELP WILL GIVE 10 POINTS!!!!

Physics

2 answers:

Leokris [45]4 years ago

4 0

Answer:

The answer is A

Explanation:

katrin2010 [14]4 years ago

3 0

The correct answer would be A

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Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How

zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

$angle = \frac{1 Parsec}{distance}$

so we have

$distance = \frac{1 Parsec}{angle}$

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

$d_a = \frac{1 Parsec}{1} = 1 Parsec$

distance of star B is given as

$d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec$

So star A is closer than star B

7 0

3 years ago

The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C

aniked [119]

The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is is 8 times the initial amount of heat.

The temperature increment will lead to the increase in the internal energy of the object. This internal energy is the heat.

Given is the change in temperature ΔT = 7-4 =3°C., diameter D to 2D,

Q = Cp x ρ(4π/3)D³ x 3..................(1)

and Q' = Cp x ρ(4π/3)(2D)³ x 3

Q' = Cp x ρ(4π/3)8D³x 3..................(2)

Dividing both the equation, we have

Q' / Q =8

Q' = 8Q

Thus, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is 8 times the initial amount of heat.

Learn more about heat.

brainly.com/question/1429452?

#SPJ1

5 0

2 years ago

IIIIIII-PLEASE HELP-IIIIII THERE ARE TWO QUESTIONS (ILL GIVE BRAINLIST)

TiliK225 [7]

Answer:

the answers should be B and D

5 0

3 years ago

Read 2 more answers

A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.

noname [10]

Answer:

The value is $\rho_s = 4.026 *10^{-6} \ C/m^2$

Explanation:

From the question we are told that

The radius of the inner conductor is $r_1 = 1 \ mm = 0.001 \ m$

The radius of the outer conductor is $r_2 = 3 \ mm = 0.003 \ m$

The potential at the outer conductor is $V = 1.5 kV = 1.5 *10^{3} \ V$

Generally the capacitance per length of the capacitor like set up of the two conductors is

$C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}$

Here $\epsilon_o$ is the permitivity of free space with value $\epsilon_o = 8.85*10^{-12} C/(V \cdot m)$

=> $C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}$

=> $C= 50.6 *10^{-12} \ F/m$

Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line charge density of the outer conductor is mathematically represented as

$\rho_l = C * V$