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3 years ago

Plz answer this now anyone plz

Physics

1 answer:

Gwar [14]3 years ago

3 0

Answer:

dx = - 0.0789[m]

Explanation:

In order to solve this problem, we must remember that the vertical component of a vector can be determined using the opposite catheter of the right triangle, by means of the sine function.

$d_{x}=0.250*sin(18.4)\\d_{x} = 0.0789 [m]$

Since the component is directed down, the sign is negative.

dx = - 0.0789[m]

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PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!

DaniilM [7]

The correct answer would be to express large and small numbers.

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3 years ago

Not in book

umka2103 [35]

Answer:

$x=2.4365\ m$

and

$x=-1.4365\ m$

Explanation:

Given:

first charge, $q_1=5\times 10^{-3}\ C$

second charge, $q_2=3\times 10^{-3}\ C$

position of first charge, $x_1=-2\ m$

position of second charge, $x_2=-1\ m$

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

$E_1=E_2$

since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

$\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}$

$\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}$

$3(r^2+1+2r)=5r^2$

$2r^2-6r-3=0$

$r=3.4365 \&\ r=-0.4365$

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

$x=-1+3.4365=2.4365\ m$

and

$x=-1-0.4365=-1.4365\ m$

6 0

3 years ago

Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzz

amid [387]

Answer:

Explanation:

The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source, or the wave source is moving relative to the observer, or both.

if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.

The frequency is the inverse from the wavelength, so the frequency heard will increase.

The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.

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3 years ago

HELP THIS IS DUE TODAY PLEASE

Sonja [21]

It’s me again lol you’re questions are simple the formula is given in the triangle
The answer is C 39 hz

Please look at the attached image below for the explanation

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2 years ago

A physicist hangs a 150-g object on a spring whose spring constant is a value of 13.22 Newtons/meter and has a spring force of 2

Nataly_w [17]

Answer:

so the answer is this because the answer is that

Explanation:

and the reason why the answer is this and that is because the answer is that

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2 years ago