2 years ago

if you changed the direction of electron flow by switching the connections to the battery what would happen

Physics

1 answer:

Rudiy272 years ago

7 0

If you changed the flow you would technically change the elections to a positive charge

You might be interested in

An object moves 2.5 m. This is an example of a _______.

makvit [3.9K]

The correct answer is A. Distance

Hope this helps

7 0

3 years ago

Read 2 more answers

Which is a mixture?

Orlov [11]

Answer:

gas

Explanation:

6 0

3 years ago

How must a force be applied to cause resonance?

Aleonysh [2.5K]

Answer:

At its most natural frequency. ... A forceful voice, exquisite control of frequency, and oscillating

8 0

3 years ago

g (12 points) The time between incoming phone calls at a call center is a random variable with exponential density p(x) = 1 r e

rusak2 [61]

Answer:

$(1)p(x)\geq 0\\(2)\int_{0}^{\infty} p(x) dx=0$

Explanation:

A function f(x) is a Probability Density Function if it satisfies the following conditions:

$(1)f(x)\geq 0\\(2)\int_{0}^{\infty} f(x) dx=0$

Given the function:

$p(x)=\dfrac{1}{r}e^{-x/r} \: on\: [0,\infty), where\:r=\dfrac{20}{ln(2)}$

(1)p(x) is greater than zero since the range of exponents of the Euler's number will lie in $[0,\infty).$

(2)

$\int_{0}^{\infty} p(x)=\int_{0}^{\infty} \dfrac{1}{r}e^{-x/r}\\=\dfrac{1}{r} \int_{0}^{\infty} e^{-x/r}\\=-\dfrac{r}{r}\left[e^{-x/r}\right]_{0}^{\infty}\\=-\left[e^{-\infty/r}-e^{-0/r}\right]\\=-e^{-\infty}+e^{-0}\\SInce \: e^{-\infty} \rightarrow 0\\e^{-0}=1\\\int_{0}^{\infty} p(x)=1$

The function p(x) satisfies the conditions for a probability density function.

6 0

3 years ago

15 The group of elements called the noble gases

kogti [31]

Answer:

C. a full outer shell of valence electrons.

Explanation:

The noble gases has a full outer shell so they don't have to react with other elements to gain or loose electrons (to have a full outer shell and be stable).

8 0

2 years ago

Read 2 more answers