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san4es73 [151]
3 years ago
10

if you changed the direction of electron flow by switching the connections to the battery what would happen

Physics
1 answer:
Rudiy273 years ago
7 0
If you changed the flow you would technically change the elections to a positive charge
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Convert 32 centimeters into inches. (1 in = 2.54 cm)
Nataly [62]

Answer: 32 centimeters is 12.5984 inches

Explanation:

8 0
3 years ago
Read 2 more answers
What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?
krok68 [10]

Answer: m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }

It is given that:

Density of material =ρ

radius of inner spherical shell = r_1

radius of outer spherical shell=r_2

we know that the volume of sphere is \frac{4}{3}\pi r^{3}

Volume of the given spherical shell = \frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }


6 0
3 years ago
c) If the ice block (no penguins) is pressed down even with the surface and then released, it will bounce up and down, until fri
eduard

Answer:

y = 20.99 V / A

there is no friction    y = 20.99 h

Explanation:

Let's solve this exercise in parts: first find the thrust on the block when it is submerged and then use the conservation of energy

when the block of ice is submerged it is subjected to two forces its weight  hydrostatic thrust

         

              F_net= ∑F = B-W

the expression stop pushing is

              B = ρ_water g V_ice

where rho_water is the density of pure water that we take as 1 10³ kg / m³ and V is the volume d of the submerged ice

We can write the weight of the body as a function of its density rho_hielo = 0.913 10³ kg / m³

             W = ρ-ice g V

              F_net = (ρ_water - ρ_ ice) g V

this is the net force directed upwards, we can find the potential energy with the expression

            F = -dU / dy

            ΔU = - ∫ F dy

            ΔU = - (ρ_water - ρ_ ice) g ∫ (A dy) dy

            ΔU = - (ρ_water - ρ_ ice) g A y² / 2

we evaluate between the limits y = 0,  U = 0, that is, the potential energy is zero at the surface

             U_ice = (ρ_water - ρ_ ice) g A y² / 2

now we can use the conservation of mechanical energy

starting point. Ice depth point

             Em₀ = U_ice = (ρ_water - ρ_ ice) g A y² / 2

final point. Highest point of the block

             Em_{f} = U = m g y

as there is no friction, energy is conserved

            Em₀ = Em_{f}

            (ρ_water - ρ_ ice) g A y² / 2 = mg y

let's write the weight of the block as a function of its density

            ρ_ice = m / V

            m = ρ_ice V

we substitute

             (ρ_water - ρ_ ice) g A y² / 2 = ρ_ice V g y

              y = ρ_ice / (ρ_water - ρ_ ice) 2 V / A

let's substitute the values

             y = 0.913 / (1 - 0.913) 2 V / A

             y = 20.99 V / A

This is the height that the lower part of the block rises in the air, we see that it depends on the relationship between volume and area, which gives great influence if there is friction, as in this case it is indicated that there is no friction

                V / A = h

where h is the height of the block

                 y = 20.99 h

7 0
4 years ago
Can someone help me please?
ipn [44]

Answer:

The starting position is 3 m and the object is traveling at 3 m/s

Explanation:

4 0
4 years ago
05
yKpoI14uk [10]

Answer:

Option C. Rate of change of velocity

Explanation:

To know the correct answer to the question, it is important we know the definition of power.

Power can be defined as the rate at which work is done. Mathematically, it is expressed as:

Power = work / time

Work and energy has the same unit of measurement i.e joule. Thus, power can also be defined as the rate at which energy is transferred i.e

Power = enery / time

Energy is measured in Joules and time in second. Thus, power can also be defined as amount of joules transfered per second.

Power = Joule / sec

The rate of change of velocity on the other hand is termed acceleration.

Thus, the answer to the question is option C.

3 0
3 years ago
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