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3 years ago

Which type of protein adds a phosphate group to another molecule?

Physics

1 answer:

7nadin3 [17]3 years ago

8 0

Answer:

Kinase Enzyme

Explanation:

Kinase is an enzyme that catalyzes a biochemical reaction where it transfers phosphate groups from high-energy, phosphate-donating molecules to specific substrates. This process is known as phosphorylation. During phosphorylation, the substrate gains a phosphate group and the high-energy ATP molecule donates a phosphate group.

Kinases belong to the enzyme family of phosphotransferases. Kinases are different from phosphorylases, as the latter catalyzes the reaction where inorganic phosphate is added to the substrate. Therefore, kinases are essential enzyme in human physiology.

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Two 3 kg spherical masses are connected by a 20 m long thread of negligible mass that does not stretch. The masses are charged s

Yuri [45]

Answer:

The charge of each sphere is $q = - 1.84 *10^{-4}C$

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

The mass of the two sphere is $m = 3 \ kg$

The length of the connection is $l = 20\ m$

The angle between the suspended side is $\theta = 17 ^o$

At Equilibrium the force acting at the horizontal is = 0N and the net force acting at the vertical is zero

This can be represented mathematically as

$\sum F_y = 0N , \ \ and \ \ \sum F_x = 0N$

For $\sum F_y = 0N$

$T cos \theta = mg$

=> $cos \theta = \frac{mg}{T}$

For $\sum F_x = 0N$

$T sin \theta = F$

=> $sin \theta = \frac{F}{T}$

Now $tan \theta = \frac{sin \theta }{cos \theta }$

$= \frac{\frac{F}{T} }{\frac{mg}{T} }$

$= \frac{F}{mg}$

Where F is the electrical force which is mathematically represented as

$F = \frac{kq^2}{r^2}$

Therefore

$tan \theta = \frac{kq^2}{mgr^2}$

Where $r$ is the distance between the two masses and from the diagram it is

$r = 2l sin \theta$

$tan \theta = \frac{kq^2 }{(2l sin \theta )^2 * mg}$

making q the subject of the formula

$q = \sqrt{\frac{mg}{k} * tan \theta (2l sin \theta )^2 }$

Where k is the Coulomb's constant with a value of $k = 9*10^{9} kg \ cdot m^3 s^{-4} A^{-2}$

Substituting values

$q = \sqrt{\frac{3 * 9.8 }{9*10^9} * tan (17) (20 sin 17)^2 }$

$q = - 1.84 *10^{-4}C$

The negative sign is because we are told from the question that they are negatively charged

8 0

3 years ago

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Which scientist is known for contributions to a scientific discipline that is different from that of the other three scientists?

Nookie1986 [14]

Archimedes is known for contributions to a scientific discipline that is different from that of the other scientists.

3 0

3 years ago

An example of unprofessional behavior is?

nika2105 [10]

B, gossiping is unproessional

7 0

3 years ago

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An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro

ivolga24 [154]

Here, we know, according to 3rd Equation of Kinematics,
v² - u² = 2as

Here, u = 0 [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values,
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!

8 0

3 years ago

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Two ropes have equal length and are stretched the same way. The speed of a pulse on rope 1 is 1.4 times the speed on rope 2. Par

kondor19780726 [428]

Answer:

m1/m2 = 0.51

Explanation:

First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:

V = √F/u

This is the equation that describes the relation between speed of a pulse and a force exerted on it.

the value of "u" is:

u = m/L

Where m is the mass of the rod, and L the length.

Now, for the rod 1:

V1 = √F/u1 (1)

rod 2:

V2 = √F/u2 (2)

Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:

1.4V2 = √F/u1 (3)

Replacing (2) in (3):

1.4(√F/u2) = √F/u1 (4)

Now, let's solve the equation 4:

[1.4(√F/u2)]² = F/u1

1.96(F/u2) =F/u1

1.96F = F*u2/u1

1.96 = u2/u1 (5)

Now, replacing the expression of u into (5) we have the following:

1.96 = m2/L / m1/L

1.96 = m2/m1 (6)

But we need m1/m2 so:

1.96m1 = m2

m1/m2 = 1/1.96

m1/m2 = 0.51

5 0

4 years ago