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STALIN [3.7K]
3 years ago
10

Sound waves are all

Physics
1 answer:
elixir [45]3 years ago
8 0

Answer:

transverse waves

Explanation:

sound waves are all transverse waves

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If each of the three rotor helicopter blades is 3.50 m long and has a mass of 120 kg , calculate the moment of inertia of the th
devlian [24]

Answer:

1470kgm²

Explanation:

The formula for expressing the moment of inertial is expressed as;

I = 1/3mr²

m is the mass of the body

r is the radius

Since there are three rotor blades, the moment of inertia will be;

I = 3(1/3mr²)

I = mr²

Given

m = 120kg

r = 3.50m

Required

Moment of inertia

Substitute the given values and get I

I = 120(3.50)²

I = 120(12.25)

I = 1470kgm²

Hence the moment of inertial of the three rotor blades about the axis of rotation is 1470kgm²

7 0
3 years ago
What are 5 examples of balanced and unbalanced forces in your home?
ryzh [129]
Balance:
a book resting on a table
a car driving at 10 miles per hour in constant velocity
a cat sitting on a chair
a bulb that attach to the ceiling 
your grandma sleeping on a bed
Unbalance:
your brother sprinting across the kitchen
a ball rolling at 5 m/s^2 
your mom trying to run at 2 m/s^2 to spank you 
you dropping your coffee mug on a floor
a cat jumping out of your bed
a tear from your eye falling through the floor
Hope this helps
8 0
3 years ago
???????????!??!!!!!!!!​
Diano4ka-milaya [45]
The answer would be B.

6 0
3 years ago
If an object is symmetrical its axis of symmetry would be in the center??
balu736 [363]
Yes i think

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6 0
3 years ago
A 21500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the
GalinKa [24]

Answer:\theta =79.47 North\ of\ west

Explanation:

Given

Mass of airplane =21500 kg

Force due to jet engines=35100 N

Force from wind is 14900 N at angle of 75 south of west

Resolving forces

F_x=14900cos75=-3856.403 N

F_y=35100-14900sin75

F_y=35100-14392.29=20707.70 N

Therefore acceleration in x direction

a_x=\frac{F_x}{m}=\frac{-3856.403}{21500}=-0.179 m/s^2

a_y=\frac{F_y}{m}=\frac{20707.70}{21500}=0.963 m/s^2

Direction of acceleration

tan\theta =\frac{a_y}{a_x}=\frac{0.963}{0.179}=-5.38

\theta =79.47\ North\ of\ west

5 0
3 years ago
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