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fomenos
3 years ago
10

An example of unprofessional behavior is?

Physics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:b. gossiping about a client's pet

Explanation:

An example of unprofessional behavior is gossiping about a client's pet.

This type behavior shows the employee mentality that he/she is not focused on his/her work and as a result his productivity will need not be as per company requirement .This type of employee is not an asset bu a liability to company.

nika2105 [10]3 years ago
7 0
B, gossiping is unproessional
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A certain baryon (a subatomic particle) has a charge q > 0. The baryon moves with a kinetic energy K in a circular path of ra
Licemer1 [7]

Answer:

v=\frac{2K}{RqB}

m=\frac{(RqB)^2}{2K}

Explanation:

The formula for kinetic energy <em>K</em> of a particle of mass <em>m</em> moving at velocity <em>v</em> is K=\frac{mv^2}{2} and the formula for the Lorentz force <em>F</em> experimented by a particle of charge <em>q </em>and velocity <em>v</em> under a magnetic field <em>B</em> is (asuming <em>v</em> and <em>B</em> are perpendicular) F=qvB.

Since the particle would be moving in circles, this force would be a centripetal force given by F_{cp}=ma_{cp}=\frac{mv^2}{R}, where <em>R</em> is the radius of the trajectory.

Then we have (<em>q, K, R</em> and <em>B</em> would be what we know):

F=F_{cp}

qvB=\frac{mv^2}{R}=\frac{2K}{R}

v=\frac{2K}{RqB}

And:

m=\frac{2K}{v^2}=\frac{2K(RqB)^2}{(2K)^2}=\frac{(RqB)^2}{2K}

7 0
4 years ago
Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the ang
vfiekz [6]
Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply. check all that apply. the angular velocity depends upon the length of the incline. the angular velocity depends upon the mass of the sphere. the angular velocity depends upon the radius of the sphere. the angular velocity depends upon the height of the incline
8 0
3 years ago
If the mass of both weights is 225 gm, the first mass is located 20∘ north of east, the second mass is located 20∘ south of east
Montano1993 [528]

Answer:

The voltage is 2.114 V.

Explanation:

Given that,

Mass of both weights = 225 gm

Transducer sensitivity = 0.5 V/N

The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,

We need to calculate the net equivalent force

Using formula of force

F_{3}=m_{1}g\cos\theta+m_{2}g\cos\theta

F_{3}=2mg\cos\theta

Put the value into the formula

F_{3}=2\times0.225\times10\cos20^{\circ}

F_{3}=4.228\ N

We need to calculate the voltage

Using formula of voltage

Voltage =sensitivity\times F_{3}

Put the value into the formula

Voltage=0.5\times4.228

Voltage =2.114\ V

Hence, The voltage is 2.114 V.

7 0
3 years ago
You have been asked to participate on the selection committee for a new textbook for the course you will be teaching in the upco
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you can eat burrito with hot taco and if school like?

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3 years ago
Which statement is true according to Hooke's law?
Mkey [24]

Hooke's law:

F = -kx

F is the spring force, k is the spring constant, and x is the displacement of the spring. The negative sign is there to indicate that the force acts in the opposite direction of the displacement (e.g. if you stretch a spring towards the right, you will feel a force pulling towards the left).

Looking at Hooke's law, the magnitude of the force is directly proportional to its displacement; that is to say, if the displacement increases, so does the magnitude of the spring force, and if the magnitude of the force increases, this necessitates an increase in the displacement.

1. As the force on a spring increases, the distance it stretches decreases.

An increase in force necessitates an increase in displacement. This statement is false.

2. As the force on a spring increases, the distance it stretches increases.

An increase in force necessitates an increase in displacement. This statement is true.

3. As the force on a spring increases, the spring's length remains unchanged.

An increase in force necessitates an increase in displacement. This statement is false.

4. The distance a spring stretches has nothing to do with how much force is applied to it.

Hooke's law shows that the spring force and its displacement are very much dependent on each other. This statement is false.

Only statement 2 is true. As the force on a spring increases, the distance it stretches increases.

3 0
3 years ago
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