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Arturiano [62]
3 years ago
8

Compare and contrast the uses of iron triad and the use of coinage metals

Chemistry
2 answers:
Arlecino [84]3 years ago
7 0
<span>Answer: Iron triad are used in the process to create steel and other metal mixtures. Coinage Metals are used for much more than just coins, and many other elements besides these are made into coins.</span>
ohaa [14]3 years ago
7 0

Iron triad is Iron , cobalt and nickel

the use of this iron triad is it is used as alloy as steel.

coinage metal is copper, silver and gold : in them all metals are transition metals and all are less reactive

coinage metals are used in jewellary (silver and gold)

copper is used in wiring of electricity.

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HELP ME PLSSSSS THIS TEST IS TIMED!!!! Write a conclusion statement that addresses the following questions: • How did your exper
SVETLANKA909090 [29]

Although the data for the experiment was not provided, we can offer a generalized answer in that when performing an experiment to achieve absolute zero temperatures, the value will never match the exact value.

<h3 /><h3>What is absolute zero?</h3>

Absolute zero is the lower limit of temperature. It is considered the coldest possible temperature that can exist. However, any attempt to reach this temperature in a controlled environment has failed, <u>scientists do not think it is possible to recreate this </u><u>temperature</u><u>. </u>

Therefore, we can confirm that the value of the absolute zero experiments did not match the accepted value. If the hypothesis was that it would be difficult or impossible to achieve, then the data would support the hypothesis, otherwise, it would fail to do so.

In summary, absolute zero is a temperature that cannot be recreated in a lab, so the value in this experiment does not match the accepted value and there is <u>no further exploration </u>to be done on this matter.

To learn more about absolute zero visit:

brainly.com/question/79835?referrer=searchResults

4 0
2 years ago
If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will
shusha [124]

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant  and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 =  78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78× 21 / 900 = 45×V2 / 750

1638/900 = 45 V2 / 750

1638×750 = 900×45V2

1228500 = 40500V2

Divide both sides by 40500

1228500÷40500= V2

V2 = 30.33L

I hope this was helpful, please mark as brainliest

6 0
3 years ago
Write balanced complete ionic equation for hcl(aq)+lioh(aq)→h2o(l)+licl(aq) express your answer as a chemical equation. identify
Svet_ta [14]

Explanation:

An equation is said to be balanced when the number of atoms on both reactant and product side are equal in number.

Whereas an equation where electrolytes in an aqueous solution are represented as dissociated ions is known as an ionic equation.

For example, HCl(aq) + LiOH(aq) \rightarrow H_{2}O(l) + LiCl(aq) can be represented in ionic form as follows.

   H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow H_{2}O(l) + Li^{+} + Cl^{-}

Now, cancelling the common ions present on both sides of the equation. The resulting, ionic equation will be as follows.

                 H^{+} + OH^{-} \rightarrow H_{2}O(l)

8 0
3 years ago
Read 2 more answers
What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

Explanation:

Given: M_{1} = 0.1 M,    V_{1} = ?

M_{2} = 0.5 M,       V_{2} = 100 mL

Formula used to calculate the volume of water is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

7 0
3 years ago
The law of reflection states that if the angle of incidence is 43 degrees, the angle of reflection is ___ degrees.
Vesna [10]

43 degrees

angle of reflection is equal to the angle of incidence

4 0
3 years ago
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