N⁻²2H4(l) + 2H2O⁻¹2(l) → N⁰2(g) + 4H2O⁻²(g)
N is oxidized and O is reduced
The concept that this best illustrates is replication.
<span>The Ionization energy decreases because the full s orbital shields the electron entering the p orbital. This is known as "shielding", When each new electron experiences attraction from the nucleus and repulsion forces from the S orbitals, the net force on outer shell electrons is significantly smaller. Therefore, ionization energy decreases during these groups.</span>
Noble gases having col:18
so the valence shell is D.8
Answer: color patterns
Explanation: can i get brainliest
