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stepan [7]
2 years ago
10

The primary use of alkanes is Question 8 options: A) drugs. B) combustion as fuels. C) food. D) polymers.

Chemistry
1 answer:
svp [43]2 years ago
4 0

Answer:

B) combustion as fuels

Explanation:

This combustion fuel is called natural gas which contains both methane and ethane

.

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Find the new pressure of 5 L of a gas at STP that is cooled to 250 K and expanded to 6L
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I’m so sorry i have to do this 5L 24
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What type of landforms do we have in Florida?
Bingel [31]

Answer:

Flora and Fauna

Explanation:

therethere are four main regions which are each home to specific landforms, flora and fauna the. These are the upland, the Everglades, the Florida Keys and the Gulf Coast

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3 years ago
Read 2 more answers
100.0 g of 4.0°C water is heated until its temperature is 37.0°C. If the specific heat of water is 4.184 J/g°C, calculate the am
Lady bird [3.3K]

Answer:

13.8072 kj

Explanation:

Given data:

Mass of water = 100.0 g

Initial temperature = 4.0 °C

Final temperature = 37.0°C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 37.0°C -  4.0 °C

ΔT = 33.0°C

Q = 100.0 g ×4.184 j/g.°C × 33.0°C

Q = 13807.2 j

Joule to KJ:

13807.2 j  × 1kj  /1000 j

13.8072 kj

5 0
3 years ago
Rutherford’s gold foil experiment demonstrated that
iVinArrow [24]

Answer:

Explanation:

The space between the large nucleus and the electrons is huge. We know this because the alpha particles shot at the gold foil most went right on through. That means that the space between hold atoms is very large.

B

Not only that but the deflection that takes place is not frequent further telling us that the the nucleus must be positively charged. That observation comes from the deflection itself. The charge on the nucleus must be the same as the alpha particle. If they were different, and the nucleus was negative, those particles that were deflected would now be absorbed.

4 0
2 years ago
49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w
inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The  value is  \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

Explanation:

From the question we are told that

   The volume of the stock solution is  V_1   =  49.9 mL  =  0.0499 \  L  

   The concentration of the stock solution is  C_1  =  0.00292 \  M

   The volume of the diluted solution is  V_2 =  1.00 \  L

   The absorbance is  A =  0.600

Generally the from the titration equation we have that

         C_1 * V_1 =  C_2 * V_2

=>      0.00292  * 0.0499 =  C_2 * 1

=>     C_2 = 0.0001457 \  M

Generally from  Beer's law we have that

      A  =  \epsilon  * l  *  C_2

=>   \epsilon  =  \frac{A}{ l  *  C_2 }

Here  l is the length who value is  1 cm because the unit of  molar  absorptivity coefficient of the dye is M^{-1} *  cm^{-1}

So

            \epsilon  =  \frac{0.600}{ 1   * 0.0001457   }  

=>       \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

4 0
3 years ago
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