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4 years ago

What is the formula unit for a compound made from Pb4+ and oxygen?

Chemistry

2 answers:

Volgvan4 years ago

8 0

Maybe Lead and Oxygen?

seropon [69]4 years ago

3 0

Answer: The formula unit of compound made up from $Pb^{2+}$ and oxygen is $PbO_2$ .

Explanation:

$Pb^{4+}+O^{2-}\rightarrow PbO_2$

When lead ion with '4+' charge binds with an oxygen anion with '2-'it forms lead(IV) oxide. The formula unit of the lead (IV) oxide according to criss cross method is written as $PbO_2$ .

Refer to the image attached.

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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

Kipish [7]

Answer: 72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles$

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry:

1 mole of $C_3H_8$ requires 5 moles of oxygen

0.45 moles of $C_3H_8$ require= $\frac{5}{1}\times 0.45=2.25$ moles of oxygen

Mass of $O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g$

72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

7 0

3 years ago

Zinc chloride (ZnCl2) and hydrogen (H2) are the products of a single replacement reaction. What are the reactants of this reacti

Juli2301 [7.4K]

The reactants of the reaction of single replacement that produces ZnCl₂ and H₂ is Zn + 2HCl

Explanation

In a single replacement reaction is a chemical reaction whereby an element react with compound and take the place of another element in that compound.

zn displaces H from HCl to form ZnCl₂ and H₂ according to below equation.

Zn +2HCl → ZnCl₂ + H₂

4 0

3 years ago

Read 2 more answers

Copper has two naturally occurring isotopes, 63Cu Gsotopic mass 629396 arnu) and 65Cu Osotopic mass 64.9278 amu). If copper has

madam [21]

Answer: The percentage abundance of $_{29}^{63}\textrm{Cu}$ and $_{29}^{65}\textrm{Cu}$ isotopes are 75.77% and 24.23% respectively