Answer:
Part A
The volume of the gaseous product is 
Part B
The volume of the the engine’s gaseous exhaust is 
Explanation:
Part A
From the question we are told that
The temperature is 
The pressure is 
The of 
The chemical equation for this combustion is
The number of moles of 
that reacted is mathematically represented as
The molar mass of is constant value which is
So 
The gaseous product in the reaction is 
and water vapour
Now from the reaction
2 moles of will react with 25 moles of 
to give (16 + 18) moles of and 
So
1 mole of will react with 12.5 moles of to give 17 moles of and
This implies that
0.8754 moles of will react with (12.5 * 0.8754 ) moles of to give (17 * 0.8754) of and
So the no of moles of gaseous product is
From the ideal gas law
making V the subject
Where R is the gas constant with a value 
Substituting values
Part B
From the reaction the number of moles of oxygen that reacted is
The volume is
No this volume is the 21% oxygen that reacted the 79% of air that did not react are the engine gaseous exhaust and this can be mathematically evaluated as
Substituting values
A mole of CO2 = 2 moles of O2
8 CO moles x 2 =
16 moles
Wym kingdom? I dont get it
Answer:
The one that is oxidized or the reducing agent
Explanation:
Oxidation results in loss of electrons or an increase in oxidation state.
Reduction results in gain of electrons or decrease in oxidation state.
The element that undergoes oxidation is said to oxidised, similarly the element that undergoes reduction is said to be reduced.
In a redox reaction, both oxidation and reduction takes place.
If a substrate undergoes oxidation or is oxidised, it is also responsible for reduction of the other species, as the total number of electrons should always be conserved.
The substance that undergoes oxidation, releases some electrons, these electrons are taken by the other substrate and it undergoes reduction.
Hence the substance that undergoes oxidation is called the reducing agent, as it is responsible for reduction of other substrate, when oxidizing itself.
Similar thought works for a substance that undergoes reduction or is reduced, works as an oxidizing agent.
Answer:
The ideal gas law can be used in stoichiometry problems in which chemical reactions involve gases. Standard temperature and pressure (STP) are a useful set of benchmark conditions to compare other properties of gases. At STP, gases have a volume of 22.4 L per mole.
