3.5 moles of ammonia (NH₃) are produced
Explanation:
We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):
3 H₂ + N₂ → 2 NH₃
number of moles = mass / molecular weight
number of moles of N₂ = 48.97 / 28 = 1.75 moles
We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.
Knowing this we devise the following reasoning:
if 1 mole of N₂ produces 2 moles of NH₃
then 1.75 moles of N₂ produces X moles of NH₃
X = (1.75 × 2) / 1 = 3.5 moles of NH₃
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limiting reactant
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