Explanation:
An elimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one or two-step mechanism. The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction.
Another definiton is;
Elimination reaction, any of a class of organic chemical reactions in which a pair of atoms or groups of atoms are removed from a molecule, usually through the action of acids, bases, or metals and, in some cases, by heating to a high temperature. It is the principal process by which organic compounds containing only single carbon-carbon bonds (saturated compounds) are transformed to compounds containing double or triple carbon-carbon bonds (unsaturated compounds).
Strong Acids play two key roles in elimination reactions:
1. Without the acid catalyst, the reaction is painfully slow.
2. Acid greatly facilitates elimination of the leaving group.
Answer:
1. 77.5g,
2. 1.78 mol,
3. 281 g
4. add 80 mL of water
Explanation:
1. Molar mass (Na2O) = 2*23.0 + 16.0 = 62.0 g/mol
1.25 mol *62.0 g/1mol = 77.5 g Na2O
2. Molar mass (KOH) = 39.1 +16.0+1.0 = 56.1 g/mol
100 g * 1 mol/56.1 g = 1.78 mol KOH
3. Molar mass (KOH) = 39.1 +16.0+1.0 = 56.1 g/mol
5 mol * 56.1g/1 mol = 281 g KOH
4. M1V1 =M2V2
M - molarity, V- volume of solution
2.0M*20mL = 0.4M*V2
V2 = 2.0*20/0.4 = 100 mL
Volume of diluted solution = 100 mL
We have 20 mL of solution, we need 100 mL of solution,
so we need to add (100-20) =80mL of water.
Take 20 ml 2.0 Molar of solution of HCl , add 80 mL of water, then we get 100 mL 0.4 M solution of HCl.
Answer: The electronic configuration of potassium atom in excited state is 
Explanation:
There are 2 states classified under energy levels:
1. Ground state: This is the lower energy state which is termed as stable state.
2. Excited state: This is the upper energy state and is termed as the unstable state. All the electrons which are present in this state always come back to the ground state.
Ground state electronic configuration of potassium (Z = 19) : 
As, only 1 electron can freely move to upper state. Hence, the excited state electronic configuration of potassium will be:
Answer:
Conversion factor is 6.022 ×10^23 molecules/mole.
Number of moles is 5.845 moles
Explanation:
We are given;
3.52 × 10^24 molecules
Required to determine the conversion factor\
We know that according to the Avogadro's constant;
1 mole of a compound contains 6.022 ×10^23 particles
Therefore, 1 mole of a molecular compound contains 6.022 ×10^23 molecules.
Thus, the conversion factor in this case would be 6.022 ×10^23 molecules/mole.
Such that; 3.52 × 10^24 molecules are equivalent to;
= 3.52 × 10^24 molecules ÷ 6.022 ×10^23 molecules/mole.
=5.845 moles
Thus, the conversion factor is 6.022 ×10^23 molecules/mole.
Number of moles is 5.845 moles
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